Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).
Usually the controlled experiment is the one that is not tested so they look at the experimental experiment to find the differences. Sorry if this doesn't answer your question.
Answer:
HNO3 and NaOH
Explanation:
A neutralization reaction is a reaction that occurs between an acid and a base to form salt and water only.
Neutralization reactions are commonly carried out by method of titration. That is, a measured volume of acid of unknown concentration is made to react with a known volume of standard base solution or vice versa.
Two reactants that could be titrated to obtain sodium nitrate are nitric acid and sodium hydroxide.
The reaction equation is as follows;
HNO3(aq) + NaOH(aq) ----> NaNO3(aq) + H2O
2HNO3 + Ca(OH)2 —> Ca(NO3)2 + 2H2O
