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Novay_Z [31]
2 years ago
12

HELP ASAP GIVING BRANLIST 100 POINTS!!!

Mathematics
2 answers:
Sedbober [7]2 years ago
6 0

Rate of change between 1 and 3: find the y values for 1 and 3:

Rate of change = (6-1) / (3-1) = 5/2

Rate of change from 2 and 4:

= (10-3) / (4-2) = 7/2

The rate from 2 to 4 is larger because 7/2 is larger than 5/2

vaieri [72.5K]2 years ago
3 0

Answer:

see below

Step-by-step explanation:

We need to find the slope

m = (y2-y1)/(x2-x1) for the points (1,1) and (3,6)

m = (6-1)/ (3-1)

   = 5/2

the average rate of change is 5/2

m = (y2-y1)/(x2-x1) for the points (2,3) and (4,10)

m= (10-3)/(4-2)

  = 7/2

the average rate of change is 7/2

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Answer:

Step-by-step explanation:

142

5 0
3 years ago
(b) Given that
Gnesinka [82]

Answer:n=-2 or n=4

Step-by-step explanation:

Q is not inversible if det(Q)=0

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4 0
2 years ago
How many ways are there for Alice, Bob, Charlie, David and Eve to line up from left to right, such that Charlie is somewhere to
steposvetlana [31]

Answer:

120 ways

Step-by-step explanation:

Alice, Bob, David, Charlie,   Eve

David, Alice, Bob,  Charlie,   Eve

Alice,David, Bob,  Charlie,   Eve

Charlie,   Eve ,Alice,David, Bob,  

Charlie,   Eve ,Alice, Bob, David,

Charlie,   Eve ,David, Alice, Bob,

Alice,Charlie,   Eve , Bob, David,

Alice,Charlie,   Eve ,  David, Bob,

Bob,Alice,Charlie,   Eve ,  David,   and so .

This is a permutation question as the order of placing Charlie to the left of Eve is important.

So the total number of people n= 5 and the possible order is 4 keeping Charlie left of Eve. Eve cannot have the last position to keep Charlie on the left.

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5! / (5-4)! = 120 ways in which Charlie can be placed to the left of Eve.

6 0
2 years ago
Here is a set of signed numbers order them least to greatest: 7, -3, , -0.8, 0.8, -, -2
Aleksandr [31]

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7 0
3 years ago
Read 2 more answers
In the diagram below <br> Please help I’ll give brainliest
Luda [366]

Answer:

m<GFA = 110

Step-by-step explanation:

1. ABCD - parallelogram                          Definition of a parallelogram

                                                                   (AB ll CD) (AD ll BC)

2. m<B + m<C = 180                                    Consectuive angles in a

   110 + m<C = 180                                       parallelogram are supplementary

    m<C = 70                                    

3. m<GCB = 1/2 m<C                                  Definition of angles bisector

   m<GCB = 70

4. m<B = m<D = 110                                    Opposite angles in a

                                                                    parrallelogram are congruent

5. m<CDG = 1/2 m<D                                 Defintion of an angle bisector

  m<CDG = 55

6. m<GCB+m<CDG+m<CGD=180              Sum of anlges in a triangle (ΔCDG)

  70 + 55 + m<CGD = 180

   125 + m<CGD = 180

   m<CGD = 55

7. m<CGD + m<DGF = 180                            Linear pair, supplmentary angles

  55 + m<DGF = 180

  m<DGF = 125

8. m<C = m<A = 70                                     Opposite angles in a paralellogram

                                                                     are congruent

9. m<ADG = 1/2m<D                                       Definiton of an angle bisector

  m<ADG = 55

10.m<ADG+m<DFG+m<GFA+m<A=360        Sum of angles in quadrilateral

   55 + 125 + m<GFA + 70 = 360                    DGFA

    m<GFA + 250 = 360

   m<GFA = 110

4 0
2 years ago
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