A box has a volume given by the trinomial x^3+4x^2-5x. What are possible dimensions of the box? Use factoring.
1 answer:
Answer: The correct answer is Choice B.
To factor this expression, we should first factor out the variable x.
We will have:
x(x^2 + 4x - 5)
Now, all we have to do is factor x^2 + 4x - 5.
The factors of this are (x + 5)(x - 1).
If you put all of the factors together, you have: x(x + 5)(x - 1) or Choice B.
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