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aleksandrvk [35]
3 years ago
7

Writing equations in standard form:

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0
You have already done half of it. Now substitute for x1 = 4 and y = 5
y - 5 = 6/7(x - 4)
Multiply everything by 7 to remove fractions
7y - 35 = 6(x - 4)
7y - 35 = 6x - 24
-6x + 7y = -24 + 35
-6x + 7y = 11

Some people prefer a positive number in front of x so multiply by -1
6x - 7y = -11

You can check the answer by testing it works for both of the original points
6x4 - 7x5 = 24 - 35 = -11 true
6x-3 - 7x-1 = -18 - -7 = -11 true
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Which shows the equation 3y – x = 6 written in slope-intercept form?
laila [671]
Slope intercept form : y = mx + b

3y - x = 6 ....add x to both sides
3y = x + 6 ...divide both sides by 3
y = x/3 + 2 <== slope intercept form


7 0
4 years ago
You know that for any , neither sin nor cos can be greater than 1. how can you explain this using the unit circle definitions of
Feliz [49]
In the unit circle the hypotenuse of the triangle formed  is equal to radius of circle , which = 1. The point on the circle formed by the intersection of the hypotenuse  is  (cos q , sin q)  where q is the angle between the x axis and the hypotenuse.   As the hypotenuse = 1 the opposite and adjacent sides of the triangle < 1   so sin and cos of q  must both be  <= 1.
4 0
3 years ago
A cone with radius 333 units is shown below. Its volume is 575757 cubic units. Find the height of the cone. Use 3.143.143, point
STatiana [176]

Answer: 6.05 units

Step-by-step explanation:

<em>Correct question is:</em>

<em>A cone with radius 3 units is shown below. Its volume is 57 cubic units. Find the height of the cone. Use 3.14 for pi and round your final answer to the nearest hundredth.</em>

Hi, to answer this question we have to apply the next formula:

Volume of a cone = 1/3 x π x radius^2 x height

Replacing with the values given:

57 = 1/3x  3.14 x (3)^2 (h)

Solving for h

57 = 1/3 x 3.14 x  9 (h)

57 =9.42h

57/9.42 =h

h= 6.05 units

Feel free to ask for more if needed or if you did not understand something.  

7 0
3 years ago
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

\dfrac{\sqrt{10}}{2}= x

Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
3 years ago
Please Explain This Function out for me :) <br> f(s) =10 (s-65)+75
netineya [11]
<span>most of the time it saids that s= a number.</span>
4 0
3 years ago
Read 2 more answers
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