Answer:
The 8th graders sold 180 more tickets
To determine if the triangle is a right triangle, we use the Pythagorean theorem to test or see if the data agrees. We do as follows:
c² = a² + b²
10² = (5√3)² + 5²
100 = 75 + 25
100 = 100
Therefore, the triangle with the given measurements is a right triangle. The angle that would have a right angle is angle BAC. Hope this answers the question. Have a nice day. Feel free to ask more questions.
Answer:
the answer for this question is
A(-3,0)
First, put the numbers in order
A. 1,2,3,4,5,7,8,8,9.....median (middle number) is 5..when there is an odd number of data values, there will only be one median.
B. 14,14,15,16,17,18,19,20....if there is an even number of data points, there will be 2 middle numbers. In that case, u add the 2 middle numbers and divide by 2 to find the median. (16 + 17) / 2 = 33/2 = 16.5 is ur median.
Answer:
b. Similar
Step-by-step explanation:
Although angles are congruent the triangles are not as sides need to be the same too. Both shapes have 90 degree and 30 degree and add up to 180 degree in each triangle. Therefore each shapes angles are congruent but we dont know there size or scale, so they are similar. if they are the same (shape and size)- in other words, if the lengths of the sides and the angles are the same. So they are similar.
Because the angles are congruent and sizes are not shown they must be similar.
They cannot be obtuse as no angle is larger than 90 degrees and to be obtuse it would have to be larger than 90 deg and lower than 180 deg.
They cannot be equilateral as that means it couldn't be 30 degree and a right angle as equilateral means same angle sizes within 'one' triangle or for every or each triangle; as we know all triangles that are equilateral are 60, 60, 60 degrees to add up to 180 degree and cannot be an equilateral for this reason too as we have right angle triangles and equilateral are not right angles due to being 60 degree angle measures.
They are not fully congruent as we do not know there side measures so they have to be similar.