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2 years ago

6

your friend claims that if a line has a slope that is less than 1, then any line perpendicular to it must have a positive slope.

Is your friend correct?

1 answer:

fomenos2 years ago

6 0

Answer:

No.

Step-by-step explanation:

A line with, say, a slope of 1/2 is still positive. a line with negative 1/2 would be perpendicular

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The are of a shaded region is 118 ft squared. Which equation can be- used to find the value of X, in feet?

Triss [41]

Answer:

$x^2+ 18x -130=0$

Step-by-step explanation:

Given

See attachment for diagram

Required

The equation to find x

First, calculate the area of the big rectangle using:

$Area = Length * Width$

So:

$A_1 = (x + 6) * (3x - 2)$

The smaller rectangle

$A_2 = (x - 1) * (2x)$

The difference between this areas give the area of the shaded region.

So:

$A_1 - A_1 = 118$

$(x+6)*(3x-2) - (x-1)*2x = 118$

Open brackets

$3x^2 - 2x + 18x -12 -2x^2 +2x = 118$

Collect like terms

$3x^2 -2x^2- 2x +2x+ 18x -12 - 118=0$

$x^2+ 18x -130=0$

<em>The above equation can be used to solve for x</em>

4 0

2 years ago

The hardware store sells green buckets, which hold 7 liters of water, and white buckets, which hold 1 liter. Austin bought 8 buc

qaws [65]

Answer: 5 green buckets and 3 white buckets

Step-by-step explanation: each green bucket is 7 liters so if Austin buys 5 of them that'll equal 35 liters already. And each white bucket is 1 liter so if he buys 3 of those that'll get him to 38

3 0

2 years ago

Can you Help me out plz!!

Klio2033 [76]

Answer:

14)

21√2

15)

Leg: 7√3

Hypotenuse: 14

Step-by-step explanation:

The hypotenuse is √2 as long as each leg. That means the leg is 42/√2. Simplified to make 21√2.

The hypotenuse is always twice as long as the shortest leg on a 30-60-90 triangle. The longer leg is √3 as long as the shortest side.

4 0

3 years ago

Jerome burned 75 calories in 15 minutes on a stationary bike. How many calories will he burn in 25 minutes

aalyn [17]

Is jerome also on stationary bicycle for next 10 minute?? if yes then he burn 125 calories at the average of 5 calorie per minute

7 0

3 years ago

Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)

Yakvenalex [24]

Answer:

$\sin d = \frac{4}{7}$ ; $\sin e = \frac{\sqrt{33} }{7}$

$\cos d = \frac{\sqrt{33} }{7}$ ; $\cos e = \frac{4}{7}$

$\tan d = \frac{4}{\sqrt{33} }$ ; $\tan e = \frac{\sqrt{33} }{4}$

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

$\sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\cos \alpha = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}$

$\tan \alpha = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }$

__________________________________________________

According to the question ,

1) When α (alpha) = d

$\sin d = \frac{4}{7}$

$\cos d = \frac{\sqrt{33} }{7}$

$\tan d = \frac{4}{\sqrt{33} }$

2) When α (alpha) = e

$\sin e = \frac{\sqrt{33} }{7}$

$\cos e = \frac{4}{7}$

$\tan e = \frac{\sqrt{33} }{4}$

3 0

2 years ago