A freight train travels 260 km in the same time a passenger train travels 320 km. If the passenger train averages 15km/hour fast
er than the freight train, what is the average speed of the freight?
1 answer:
Time = t
<span>vf t = 260 </span>
<span>vp t = 320 </span>
<span>so </span>
<span>260/vf = 320/(vf+15) </span>
<span>320 vf = 260 vf +260(15) </span>
<span>60 vf = 390 </span>
<span>3 vf = 39 </span>
<span>vf = 13 km/hour
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You're answer is D.
-3/-3(2)-9
1(2)-9
2-9
7
so it is D
The answer to 14 is 13 as in the number not the question
and 13 I'm not so sure
Your answer would be (x,y)=(2,-2)
divide by 3.14 on both sides first.
V/3.14 = r^3
Now cube root both sides.
3√(V/3.14) = r
r = 3√(V/3.14)
r is the cube root of v/3.14.
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