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IrinaK [193]
3 years ago
5

Angela's car payment is due January 31. This bill is always paid automatically from her checking account. It is January 30 and A

ngela realizes that she does not have enough money in her checking account to cover the payment. What is Angela's best option for handling the payment?
Mathematics
2 answers:
ikadub [295]3 years ago
8 0

Answer:

C - Try to call the company that holds the car loan and explain the problem and ask them not to accept the payment when it arrives.

Step-by-step explanation:

Verified through PLATO and EDMENTUM

hram777 [196]3 years ago
7 0
<span>Calling the company that holds the car loan and asking them about other repayment options is the best tactic. This allows the loan holder to negotiate terms that would be acceptable to both sides, as well as showing that Angela is trying to make a good-faith effort to repay what she can. While it may increase the overall length of time that her payments require, it also shows that she is not going to outright default on the payments.</span>
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Answer:

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Step-by-step explanation:

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Multiply both sides by y.

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Divide both sides by y.

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A line passes through the point (10,-8) and has a slope of negative 3/2Write an equation in slope-intercept form for this line.
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Answer:

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Step-by-step explanation:

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What is the length of the mid-segment DE?
astraxan [27]

Answer:

The midsegment is one-half the length of the base

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Step-by-step explanation:

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2 years ago
A researcher believes that the mean weight of competitive runners is about 140 pounds. A sample of 24 elite distance runners has
ExtremeBDS [4]

Answer:

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

p_v =P(t_{(23)}  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=136 represent the sample mean

s=11 represent the sample standard deviation

n=24 sample size  

\mu_o =140 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 140, the system of hypothesis would be:  

Null hypothesis:\mu \geq 140  

Alternative hypothesis:\mu < 140  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{136-140}{\frac{11}{\sqrt{24}}}=-1.781    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=24-1=23  

Since is a one left tailed test the p value would be:  

p_v =P(t_{(23)}  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is less than 140 pounds at 5% of signficance.  

4 0
2 years ago
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