A triangle has vertices at A ( 3 , 4 ) , B ( − 3 , 2 ) , C ( − 1 , − 4 ) . Is the triangle a right triangle? Explain.

Mathematics

1 answer:

Westkost [7]4 years ago

8 0

Answer: No

Step-by-step explanation:

The answer to this question is quite simple in the sense that all you need to do is graph the points on a graph and you can easily see that it is not a right triangle.

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Suppose the interval [negative 2,0] is partitioned into nequals4 subintervals. What is the subinterval length Upper Delta x?

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We find the length of each subinterval dividing the distance between the endpoints of the interval by the quantity of subintervals that we want.

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Δx= $\frac{0-(-2)}{4}=\frac{2}{4}=\frac{1}{2}$

Now, each $x_i$ is found by adding Δx iteratively from the left end of the interval.

$x_0=-2\\x_1=-2+\frac{1}{2}=\frac{-3}{2}\\x_2=\frac{-3}{2}+\frac{1}{2}=-1\\x_3=-1+\frac{1}{2}=-\frac{1}{2}\\x_4=\frac{-1}{2}+\frac{1}{2}=0$

Each subinterval is

$s_1=[-2,-3/2]\\s_2=[-3/2,-1]\\s_3=[-1,-1/2]\\s_4=[-1/2,0]$

The midpoints of the subintervals are

$m_1=\frac{-2-3/2}{2}=\frac{-7/2}{2}=\frac{-7}{4}\\m_2=\frac{-1-3/2}{2}=\frac{-5/2}{2}=\frac{-5}{4}\\m_3=\frac{-1/2-1}{2}=\frac{-3/2}{2}=\frac{-3}{4}\\m_4=\frac{0-1/2}{2}=\frac{-1}{4}$