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svetoff [14.1K]
2 years ago
9

Circle the possible values that satisfy each inequality!​

Mathematics
1 answer:
RoseWind [281]2 years ago
3 0

Answer:

25

Step-by-step explanation:

5 > x/5

5 × 5 > (x/5) × 5

25 > x

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What is the greatest perfect square that is a factor of 980?
BaLLatris [955]
Since 980÷2=490÷2=245÷5=49÷7=7÷7=1
980=2×2×5×7×7
the greatest perfect square will be
7*2*7*2
14*14=196
8 0
3 years ago
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1/3 ( x - 10) = -4 ???​
Pepsi [2]

Answer:

x =  - 2

Step-by-step explanation:

1) Simplify 1/3 ( x - 10) to x-10/3.

\frac{x - 10}{3}  =  - 4

2) Multiply both sides by 3.

x - 10 =  - 4 \times 3

Simplify 4 × 3 to 12.

x - 10 =  - 12

4) Add 10 to both sides.

x =  - 12 + 10

5) Simplify -12 + 10 to -2.

x =  - 2

So, therefor, the answer is, x = -2.

4 0
3 years ago
The mean of a particular set of 7 numbers is 4. Six of the numbers in the set are known: 1,2,2,5,7,and 8.
Setler [38]
\dfrac{1+2+2+5+7+8+x}{7}=4\\
\dfrac{25+x}{7}=4\\
25+x=28\\
\boxed{x=3}

8 0
3 years ago
Suppose that we don't have a formula for g(x) but we know that g(3) = −1 and g'(x) = x2 + 7 for all x.
Sliva [168]

Answer:

  • g(2.95) ≈ -1.8; g(3.05) ≈ -0.2
  • A) tangents are increasing in slope, so the tangent is below the curve, and estimates are too small.

Step-by-step explanation:

(a) The linear approximation of g(x) at x=b will be ...

  g(x) ≈ g'(b)(x -b) +g(b)

Using the given relations, this is ...

  g'(3) = 3² +7 = 16

  g(x) ≈ 16(x -3) -1

Then the points of interest are ...

  g(2.95) ≈ 16(2.95 -3) -1 = -1.8

  g(3.05) ≈ 16(3.05 -3) -1 = -0.2

__

(b) At x=3, the slope of the curve is increasing, so the tangent lies below the curve. The estimates are too small. (Matches description A.)

4 0
3 years ago
Select the problems which show the correct answers. (1.12 x 105) (6.06 x 105) Answer: 6.79 x 1010 (2 x 101)(3.0 x 101) Answer: 6
Arisa [49]
Since multiplication is commutative, we can rearrange the problem: 
(1.12*10^5)(6.06*10^5) = (1.12*6.06)(10^5*10^5)
Using the properties of exponents, we have:
(1.12*6.06)(10^10)
\\=6.7872*10^10

Again, multiplication is commutative, so we rearrange the problem; then we use the product property of exponents:
(2*10^1)(3*10^1)
\\=(2*3)(10^1*10^1)
\\=6*10^2

(2.775*10^-^4)(4.775*10^4)
\\=(2.775*4.775)(10^-^4*10^4)
\\=(2.775*4.775)(10^0)
\\=(2.775*4.775)(1)
\\=2.775*4.775=13.250625=1.3250625*10^1

5(8.14*10^2)=(5*8.14)(10^2)=40.7*10^2=4.07*10^3
6 0
3 years ago
Read 2 more answers
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