Yes, you got it! You would need to set the equations equal to each other, because that represents when their populations are the same. Then, solving for x will find the time in months until you reach that equilibrium in population. If you need help solving for x, just comment on this. Hope it helps!
Answer:
6a^2+ 2bc-2c^1/3 <u>= 162</u>
Step-by-step explanation:
![\rm = 6 + 162 - 2 ( \sqrt[3]{27} )](https://tex.z-dn.net/?f=%20%5Crm%20%20%3D%206%20%2B%20162%20-%202%20%28%20%5Csqrt%5B3%5D%7B27%7D%20%29)
The numbers are 24 and 26
Step-by-step explanation:
- Step 1: Let the integers be x and (x+2). Here the smaller integer is x and the larger integer is x + 2.
Given that 4x = 18 + 3(x + 2)
⇒ 4x = 18 + 3x + 6
⇒ 4x = 24 + 3x
⇒ x = 24 and x + 2 = 26
B.
D.
D.
4th: 1/12 and or 1/3
Coloumn A.
1.A
2.C
3.C
4.B
