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fiasKO [112]
3 years ago
11

Describe the transformation of the graph of the parent function y = √x for the function y = √x + 7 + 5.

Mathematics
2 answers:
Digiron [165]3 years ago
6 0

Answer: Its 7 units left and 5 units up.

You didn't write the question completely by the way.

Katarina [22]3 years ago
4 0

Answer:


Step-by-step explanation:

I think it 3 sorry if it’s wrong


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Combine the radicals. 3√5-8√5+2√5
weeeeeb [17]

Answer:  -3\sqrt{5}

-3 times the square root of 5

=============================================

Explanation:

Let x = \sqrt{5}

Replace all the root 5 terms with x and we go from

3\sqrt{5}-8\sqrt{5}+2\sqrt{5}

to

3x-8x+2x

From here, combine like terms to get

3x-8x+2x = -5x+2x = -3x

and the last thing to do is replace the x with sqrt(5)

-3x = -3\sqrt{5}

Meaning that,

3x-8x+2x = -3x

3\sqrt{5}-8\sqrt{5}+2\sqrt{5} = -3\sqrt{5}

7 0
3 years ago
Please help with geometry. 20 points, and another question worth 98 on my profile!
vovikov84 [41]

Answer:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) PR^{2} =PS*PT

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

PR^{2} =PS*PT

Part 3)

we know that

The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]

4 0
3 years ago
The data in the table represents a company’s profit based on the number of items produced.
expeople1 [14]

Answer: A) -1.026x2 + 1016.402x - 162075

Step-by-step explanation: I aced the test on e2020 ;)

4 0
3 years ago
Read 2 more answers
Find the lateral area for the cylinder with the given measurement. r = 4, h = 5
Ivanshal [37]
AL≈125.66<span><span><span>r-Radius</span><span>h-Height</span></span></span>
4 0
4 years ago
How does the graph of g(x) = <img src="https://tex.z-dn.net/?f=%28x%2B12%29%5E%7B2%7D" id="TexFormula1" title="(x+12)^{2}" alt="
Law Incorporation [45]

Answer:

Horizontal translation of the parent graph

Step-by-step explanation:

<h2><u>Definitions</u>:</h2>

In the <u>vertex form</u> of a quadratic function, f(x) = a(x - h)² + k, where:

  • (h, k) = vertex of the graph
  • <em>a</em>  = determines the width and direction of the graph's opening.

A <u>horizonal translation</u> to the parent graph is given by, y = f(x - h), where:

  • <em>h</em> > 0 ⇒ Horizontal translation of <em>h</em> units to the right
  • <em>h</em> < 0 ⇒ Horizontal translation of |<em>h </em>| units to the left

In the graph of g(x) = (x + 12)², the <u>vertex</u> occurs at point (-12, 0).

While the <u>vertex</u> of the parent graph, f(x) = x² occurs at point, (0, 0).

<h2><u>Answers</u>:</h2>

Since the vertex of g(x) occurs at point, (-12, 0), substituting the value of (<em>h</em>, <em>k </em>) into the vertex form will result into:

g(x) = a(x - h)² + k

g(x) = [x - (-12)]² + 0

g(x) = (x + 12)² + 0

g(x) = (x + 12)²

Therefore, the graph of g(x) = (x + 12)² represents the horizontal translation of the parent graph, f(x) = x², where the graph of g(x) is <em>horizontally</em> translated 12 units to the left.  

3 0
3 years ago
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