B - the value of x is positive and the value of y is negative
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
<h3><em><u>Simplify -3y+2x-5y-7x is:</u></em></h3><h3>-8y - 5x</h3>
<em><u>Solution:</u></em>
<em><u>Given that, we have to simplify</u></em>
We can simplify the above expression by combining the like terms
Like terms are terms that has same variable ( with same exponent) with same or different coefficient
From given,
Here, like terms are -3y and -5y
And 2x and -7x
Group the like terms
Combine the like terms
Thus the given expression is simplified
Answer:
0≤x≤8
Step-by-step explanation:
the domain is basically all the x-values that are applicable to the graph.
Here we can clearly see that the graph starts at x = 0 and ends at x = 8. There are no other possible x-values which is applicable to the graph,
hence the domain is 0≤x≤8
Answer:
Mean: 50.8 or 51 (rounded)
Median: 51.5 or 52 (rounded)
Step-by-step explanation:
To find the mean I added all the numbers then divides my sum but the number of numbers.
To find the median I listed the numbers from least to greatest.There are two middle numbers so I added the two numbers and divided the same by 2.
