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3 years ago

Micah can do 75 push up in 3 minutes Edward Lowe can do 130 push-ups in 5 minutes are these rates equivalent

Mathematics

1 answer:

IrinaK [193]3 years ago

6 0

No because Edward can do 26 push-ups per minute while Micah can only do 25 push-ups per minute

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Pls help me if I cabbnnnnsbdhdhdjdjxjkxx

lakkis [162]

Answer:

33.49 mm³

Step-by-step explanation:

The formula of volume of sphere

$= \frac{4}{3} \pi {r}^{3}$

The volume of the sphere

$= \frac{4}{3} \times 3.14 \times {2}^{3}$

$= \frac{100.48}{3}$

$= 33.4933333...$

= 33.49 mm³ (rounded to the nearest hundredth)

3 0

3 years ago

What word describes the equal shares of the shape?

timurjin [86]

Partition describes the equal shares of a shape.

4 0

3 years ago

A broken calculator can double any number or permute its digits (but 0 cannot go up front). Can we start with number 1 and obtai

stira [4]

Answer: it's impossible to obtain 78

Step-by-step explanation: Since the calculator can double any number or permute its digits except 0

starting with number 1

1, 2, 4, 8, 16, 32, 64, 128

Therefore, it's impossible to obtain 78 by a series of these operations

8 0

2 years ago

Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2

valentina_108 [34]

Answer:

Solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

Step-by-step explanation:

We need to solve the equation $x^2+6x-8=0$ by completing the square method.

For completing the square method: we need to follow: $a^2+2ab+b^2=(a+b)^2$

We are given:

$x^2+6x-8=0$

Solving by completing the square

$x^2+2(x)(?)+(?)^2-8=0$

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

$x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17$

So, solving the equation $x^2+6x-8=0$ by completing the square method we get $\mathbf{(x+3)^2=17}$

Option B is correct option.

7 0

2 years ago

Find an equation in standard form for the hyperbola with vertices at (0, ±3) and foci at (0, ±7)

Nitella [24]

The equation of a hyperbola is:

(x – h)^2 / a^2 - (y – k)^2 / b^2 = 1

So what we have to do is to look for the values of the variables:

For the given hyperbola : center (h, k) = (0, 0)
a = 3(distance from center to vertices)
a^2 = 9

c = 7 (distance from center to vertices; given from the foci)
c^2 = 49

By the hypotenuse formula:
c^2 = a^2 + b^2
b^2 = c^2 - a^2

b^2 = 49 – 9

b^2 = 40

Therefore the equation of the hyperbola is:

(x^2 / 9) – (y^2 / 40) = 1

5 0

3 years ago

Read 2 more answers