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KATRIN_1 [288]
2 years ago
12

If the volume of a cylinder is 90 inches and what is the volume of a cone?

Mathematics
1 answer:
anzhelika [568]2 years ago
3 0

Answer:

  • The ans is D)1/3 in my point of view...
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Solve the equation for the red variable(C)in R-C=P
BARSIC [14]

If you want to solve the equation

R-C=P

for C, you can work like this: subtract P from both sides:

R-C-P = 0

Add C to both sides:

R-P=C

5 0
3 years ago
Please find the slope of (-2, 4) and (3, -5)
DIA [1.3K]

Answer:

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

  • (-2, 4)
  • (3, -5)  

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]  

                 =  [-5 - 4] / [3 - (-2)]

                 = [-9] / [3 + 2]

                 = -9/5

Thus, the slope of the line = m = -9/5  

8 0
3 years ago
20 x 18 x 5 properties
Artemon [7]
20 x 18 x 5= 1,800
20 times 18 equals 360, then you mutiply 5 and get 1,800
8 0
2 years ago
Write in standard form 4,000,000+3,000+50+2
Andreas93 [3]
4,003,052 is the answer to the problem
7 0
3 years ago
Read 2 more answers
What are the solutions to the following system of equations? y=x^2+12x+30 and 8x-y=10
Ierofanga [76]
Note that the 2nd equation can be re-written as y=8x-10.
According to the second equation, y=x^2+12x+30.
Equate these two equations to eliminate y:

8x-10 = x^2+12x+30

Group all terms together on the right side.  To do this, add -8x+10 to both sides.  Then 0 = x^2 +4x +40.  You must now solve this quadratic equation for x, if possible.  I found that this equation has NO REAL SOLUTIONS, so we must conclude that the given system of equations has NO REAL SOLUTIONS.

If you have a graphing calculator, please graph 8x-10  and  x^2+12x+30 on the same screen.  You will see two separate graphs that do NOT intersect.  This is another way in which to see / conclude that there is NO REAL SOLUTION to this system of equations.
6 0
3 years ago
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