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KATRIN_1 [288]
3 years ago
12

If the volume of a cylinder is 90 inches and what is the volume of a cone?

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

  • The ans is D)1/3 in my point of view...
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Suppose that prices of a certain model of new homes are normally distributed with a mean of $150,000. use the 68-95-99.7 rule to
Novosadov [1.4K]

Answer:

We want to find the percentage of values between 147700 and 152300

P(147700

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

z= \frac{x-\mu}{\sigma}

And replacing we got:

z=\frac{147700-150000}{2300}=-1

z=\frac{152300-150000}{2300}=1

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

Step-by-step explanation:

We define the random variable representing the prices of a certain model as X and the distirbution for this random variable is given by:

X \sim N(\mu = 150000, \sigma =2300

The empirical rule states that within one deviation from the mean we have 68% of the data, within 2 deviations from the mean we have 95% and within 3 deviations 99.7 % of the data.

We want to find the percentage of values between 147700 and 152300

P(147700

And one way to solve this is use a formula called z score in order to find the number of deviations from the mean for the limits given:

z= \frac{x-\mu}{\sigma}

And replacing we got:

z=\frac{147700-150000}{2300}=-1

z=\frac{152300-150000}{2300}=1

So then we are within 1 deviation from the mean so then we can conclude that the percentage of values between $147,700 and $152,300 is 68%

7 0
3 years ago
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