A chef makes 1 in a half gallons of soup in a large pot. how many 1-cup sevings can the chef get from this large pot of soup?

¿por que en los mapas se respeta la misma escala? Ayudenme por favor esta es otra pregunta ¿qué pasaría si una parte del mapa se

7nadin3 [17]

Answer:

Ok, supón que conoces exactamente tu posición en un mapa, y también sabes a donde quieres ir.

Podes ver en ese mapa la distancia entre tu posición y el lugar al que quieres ir, ahora, si la escala del mapa es conocida (por ejemplo 1cm = 1km) y constante, entonces vos podes medir la cantidad de centímetros entre tu posición y tu destino, y multiplicar ese numero por la escala, de esta forma conociendo la distancia real entre tu posición y tu destino.

Ahora, si la escala no es constante, entonces es imposible saber exactamente la distancia entre nuestra posición y nuestro destino, entonces este mapa no sirve realmente para ubicarnos/guiarnos, entonces no funciona como un mapa.

En el caso de que una parte este en una escala y otra parte en otra, en la primera parte un centímetro en el mapa equivaldría a una distancia X en la realidad, y en la otra zona un centímetro en el mapa equivaldría a una distancia Y en la realidad.

Donde X es diferente de Y, ahora, cuando queremos calcular la distancia entre dos lugares tendríamos que saber exactamente en que lugar se da el cambio de escala (para saber si usamos X o Y). Lo que hace que leer este mapa sea bastante mas difícil que leer un mapa normal.

8 0

3 years ago

What are inverse functions?

laila [671]

If functions transfer some a to b via some formula, then inverse of such functions transfer b to a via some other formula.

Hope this helps.

8 0

3 years ago

Read 2 more answers

Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w

Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so $p = 0.6$

The week has 5 days, so $n = 5$

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102$

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768$

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304$

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456$

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so $P(X = 5)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778$

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0

4 years ago

Please help me and I’ll give you brainiest!!!!!!!!! <br><br> Thank you:)!!!!!

sattari [20]

What you have written down is correct, x=-3

4 0

3 years ago

Find the distance between this pair of parallel lines. These equations are in slope- intercept form.

garri49 [273]

Distance is -2 my dude

8 0

3 years ago