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3 years ago

A chef makes 1 in a half gallons of soup in a large pot. how many 1-cup sevings can the chef get from this large pot of soup?

Mathematics

2 answers:

attashe74 [19]3 years ago

4 0

There are 16 cups in one gallon so a half would be 8
Answer: 8 cups

kobusy [5.1K]3 years ago

3 0

16 cups equal a gallon and 8 is half of it

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if k is a half-plane determined by QR, then for every real number 0 < x < or = to 180, there is exactly one ray, QQP, that

zloy xaker [14]

Let me start from the meaning of half plane.you must have learned that there are two axes X and Y axes which includes positive X axes and negative X axes and there is positive Y axes and negative y axes. So there are four quadrants which i have explained in the figure. I have explained the meaning of Half plane in the Diagram also. Half plane=Figure obtained by covering any two adjacent regions of the coordinate axes.So we get four half planes.

Now your question is k is a half plane determined by QR, such that 0<x≤180 and there is exactly one ray QRP that lies in k

So, $0< \angle PQR \leq 180^\cir{0}$

8 0

3 years ago

Graph the line using a point and a slope. Write the equation of each line. A line that passes through the point (0, –3) and para

kiruha [24]

Y + 3 = 1.2(x - 0)

y + 3 = 1.2x - 0

y = 1.2x - 3

5 0

3 years ago

Swimming pool is 10m long, 8m wide and 4m deep. Allen wants to know the

Studentka2010 [4]

V=320
10 x 8 x 4
i think

5 0

3 years ago

Read 2 more answers

Please help, quick math, and a short explanation on how you got the answer! Thank you!!

Lostsunrise [7]

Answer:

this is an iscoceles triangle.

I know this because 2 of the sides are equal in length

Therefore,

AB=AC

3x-5=-2x+15

x-5=15

x=20

if x=20 then BC=2(20)

BC=40

Step-by-step explanation:

4 0

3 years ago

f(t)=Q0(1+r)^t. Find the growth rate, r, to the nearest thousandth, given f(0.01)=1.06 and f(0.11)=1.09.

sweet-ann [11.9K]

To find the ratio, you just need to divide the two function and solve it. The calculation would be:

<span>F(t)=Q0(1+r)^t

F(0.11)/F(0.01) = 1.09/1.06
</span>Q0(1+r)^0.11 / Q0(1+r)^0.01 = 1.0291
(1+r)^(0.11-0.01) = <span>1.0291</span>
(1+r)^0.10 = 1.0291
(1+r)^0.10*10 = 1.0283 ^10
(1+r )= 1.3325
r = 0.323

4 0

3 years ago