f(t)=Q0(1+r)^t. Find the growth rate, r, to the nearest thousandth, given f(0.01)=1.06 and f(0.11)=1.09.

1 answer:

4 0

To find the ratio, you just need to divide the two function and solve it. The calculation would be:

<span>F(t)=Q0(1+r)^t

F(0.11)/F(0.01) = 1.09/1.06
</span>Q0(1+r)^0.11 / Q0(1+r)^0.01 = 1.0291
(1+r)^(0.11-0.01) = <span>1.0291</span>
(1+r)^0.10 = 1.0291
(1+r)^0.10*10 = 1.0283 ^10
(1+r )= 1.3325
r = 0.323

You might be interested in

A sea horse riding travels an average of 0.01 miles per hour. At that rate , how fast can a sea horse travel in 2.4 hours?

kondaur [170]

As for this problem, it would be best to approach this with a ratio to ratio approach. This would then involve the equation with fractions which is the common conversion from ratios to easily solve the problems concerning these. The equation then would look somehow like this:

0.01 miles / 1 hour = x miles / 2.4 hours

The easiest way would be just to multiply the numerator, which is the miles, to 2.4. So when it is multiplied to the numerator, the equation then would turn to:

0.01 miles x 2.4 / 1 hour = x miles / 2.4 hours

0.024 miles would be the answer.

5 0

3 years ago

Read 2 more answers

Are all rational equation solutions valid?

Semenov [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe

solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for $p$ such that $1000p(1-p)$ is maximized. Once we have that $p$ , we can easily find the answer to part b.

Finding the value that maximizes $1000p(1-p)$ is the same as finding the value that maximizes $p(1-p)$ , just on a smaller scale. So, we really want to maximize $p(1-p)$ . To do this, we will do a trick called completing the square.

$p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4$ .

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of $p$ such that the inner part of the square term is equal to $0$ .