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nekit [7.7K]
3 years ago
11

Please help solve h(t) =-16t^2+40t+20​

Mathematics
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer: el último

Step-by-step explanation:

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I’m struggling a bit on this question, may someone help me please
Leto [7]

Answer:

k = 2

Step-by-step explanation:

Use a graphing calculator

6 0
3 years ago
It cost the Wilson children $55 to make lemonade. How many glasses must they sell at 75 cents each to make a profit? Write an eq
Brut [27]
To start break even they need to sell 100 but if they want to make profit they need to sell 101 because you can use the equation y = .75x - 55
7 0
3 years ago
5n+4=39 find the value of n that makes this equation true
Bond [772]
5n + 4 = 39
5n = 39 -4
5n = 35
n = 35:5
n = 7
4 0
3 years ago
Read 2 more answers
Evaluate Combination (6,6)
andrew11 [14]

Answer:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

6C6

And the general formula for combination is given by:

nCx = \frac{n!}{x! (n-x)!}

On this case n =6 and x =6 we got:

6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1

8 0
3 years ago
10) Show that in a group of 10 people (where any two people are either friends or enemies), there are either three mutual friend
ddd [48]

Answer with explanation:

Number of People in the group =10 People

The combination between two people is that, they can be either friends or enemies.

Total number of Possible Relation

                            =18 +16+14+12+10+8+6+4+2

                            = 90 Relations in all.

Out of 90 relations , 45 will be friends and 45 will be enemies.

⇒Now, we have to prove that, between 10 people, there are either three mutual friends or four mutual enemies, and there are either three mutual enemies or four mutual friends.

→→If there are three mutual friends, total number of people in the group =3 ×2=6 people in the group

And, four mutual enemies in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual friends or four mutual enemies

   =6 +4

   =10

Hence proved.

→→→→Second part is ,in this group there can be either three mutual enemies or four mutual friends.

⇒If there are three mutual enemies, total number of people in the group =3 ×2=6 people in the group

And, four mutual friends in a group means there are 2 people in each group.

So, total number of people if we combine the two groups in which there are either three mutual enemies or four mutual enemies

   =6 +4

   =10

Hence proved.

3 0
3 years ago
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