the negative - positive
- 24/-4
24/4
6
if indeed two functions are inverse of each other, then their composite will render a result of "x", namely, if g(x) is indeed an inverse of f(x), then
![\bf (g\circ f)(x)=x\implies g(~~f(x)~~)=x \\\\\\ \begin{cases} f(x) = 3x\\ g(x)=\cfrac{1}{3}x \end{cases}\qquad \qquad g(~~f(x)~~)=\cfrac{1}{3}[f(x)]\implies g(~~f(x)~~)=\cfrac{1}{3}(3x)](https://tex.z-dn.net/?f=%5Cbf%20%28g%5Ccirc%20f%29%28x%29%3Dx%5Cimplies%20g%28~~f%28x%29~~%29%3Dx%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Bcases%7D%20f%28x%29%20%3D%203x%5C%5C%20g%28x%29%3D%5Ccfrac%7B1%7D%7B3%7Dx%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%5Bf%28x%29%5D%5Cimplies%20g%28~~f%28x%29~~%29%3D%5Ccfrac%7B1%7D%7B3%7D%283x%29)
Answer:
The field will not fit
Step-by-step explanation:
To find the angle, we will use cosine rule;
c² = (a² + b² - 2abcosC)
C in this case is θ
Thus;
15² = (8² + 20² - 2(8 × 20)cos θ)
225 = (64 + 400 - 320cos θ)
464 - 225 = 320cos θ
cos θ = 239/320
θ = cos^(-1) 0.7469
θ = 41.68°
Thus angle is not less than 40° as recommended. Thus, the field will not fit.
Answer: Only the second image
Step-by-step explanation: