Answer:
1. 280/11
2. 1700/11
3. 280/11
4. 3600
5. 360
Step-by-step explanation:
Let n = sides of a regular polygon
For these problems, n = 22 because there are 22 sides.
I am going to write the formulas needed for each question below.
- 360/n
- 180 - 360/n
- 360/n
- 180(n-2)
- 360 (isn't affected by n)
To solve, just plug in N with 22.
These formulas are very easy to prove and I recommend if you have time try to prove these.
Answer:
d. $137,604
Step-by-step explanation:
The amortization formula is good for this. It tells you the principal P that must be invested to support payments of A each year for t years when the interest rate is r:
P = A(1 -(1 +r)^-t)/r
P = $12,000(1 -1.06^-20)/0.06 ≈ $137,639.05
The closest answer choice is $137,604.
Answer:
ok
Step-by-step explanation:
Answer:
Step-by-step explanation: X1=-8,Y1=1, M=5/6.
Using the formular y-y1=m(x-x1)
y-1=5/6(x-(-8)
=y-1=5/6(x+8)
y-1=5x+8/6
=6(y-1)=5x+8
6y-6=5x+8
6y-5x=8-6
6y-5x=2
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.
Similarly, we have
Now, to find the lengths of the diagonals,
So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units