Given:
In ΔJKL, m∠L=90°, JL = 80, KJ = 89, and LK = 39.
To find:
The value of sine of ∠J.
Solution:
In a right angle triangle,
In triangle JKL,
Therefore, the value of sine of ∠J is about 0.44.
What is the numerical factor of a multiplication expression like 3x
1 answer:
You might be interested in
Answer:
QR is tangent to circle P at point Q
=> RQP = 90 deg
=> RQP is right triangle.
=> Applying Pythagorean theorem for right triangle RQP:
QP^2 + QR^2 = RP^2
=>4^2 + QR^2 = RP^2
=> Option A is correct.
(4^2 + (4*)^2 = 16 + 48 = 64 = 8^2)
=> Option C is correct.
(4^2 + 3^2 = 16 + 9 = 25 = 5^2)
=> Option D is correct
(4^2 + 2^2 = 16 + 4 = 20 = (2)^2)
Hope this helps!
:)