Answer:
Step-by-step explanation:
Angle 4 = angle 1 and angle 3 =angle 2 Corresponding angles for two parallel lines BD and AE
Triangle AED ||| BDE Angle angle congruent
... By compendo and dividendo
Thus proved
Since two lines are parallel we have corresponding angles equal and also
sides will be proportional in similar triangles
Using that and adjusting compendo and dividendo we get the desired result
Let's determine the
measures of the angles
formed by two heights of an equilateral triangle.
Answer:
C=hypotenuse [h]=50 feet
A=[base]=40foot.
B=perpendicular [p]=?
Area =?
we have
By using Pythagoras law
p²+b²=h²
B²=40²=50²
B²=50²-40²
B=√900
B=30feet
we have
Area of triangle =½×A×B=½×30×40=600feet²
<u>the roped off </u><u>area</u><u> </u><u>is</u><u> </u><u>6</u><u>0</u><u>0</u><u> </u><u>square</u><u> </u><u>feet</u><u>.</u>
<u>it</u><u> </u><u>is</u><u> </u><u>a</u><u> </u><u>right</u><u> </u><u>angled</u><u> </u><u>triangle</u><u>.</u>
