Domain and Range Number 2,3,4
1 answer:
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Answer:
13 inches
Step-by-step explanation:
Let P(t) and P(s) be the perimeters of the equilateral triangle and square respectively. Similarly, t and s be the side lengths of equilateral triangle and square respectively.
According to the first condition :
(Perimeter of an equilateral triangle is 11 inches more than the perimeter of a square)
According to the second condition :
(The side of the triangle is 6 inches longer than the side of the square)
From equations (1) & (2)
3(s + 6) = 4s + 11
3s + 18 = 4s + 11
3s - 4s = 11 - 18
-s = - 7
s = 7 inches
Thus the side of the triangle is 13 inches long.