1) Area = (b*h)/2 = (9*5)/2 = 45/2 = 22.5 (Letter A)
2) Area = b*h = 8*14 = 112 (Letter D)
3) Surface area of a prism is SA=2B+ph (B = area of the base, p = perimeter of the base, h = height)
B = 15 * 5 = 75 cm^2
p = 15 + 5 = 20 cm
SA = 2*75 + 20*7 = 150 + 140 = 290 (G)
4) V = (B*H*L)/2 = (15*7*5)/2 = 525/2 = 262.5 cm^3 (G)
5) V = 9^3 = 81 cm^3 worth of wrapping (A)
6) V = (B*H*L)/2 = (13*6*8)/2 = 312 cube feet (J)
It gave me ADGGAJ. I don't know if this is right, but I atleast tried to do something, right?
Answer:
The answer will be 85,968
Answer:
61%
Step-by-step explanation:
We can see that out of all the people that were surveyed, 54% were 10th graders. Since 33% out of all the ones surveyed were 10th graders that chose robotics, the fraction would be 33/54 which is 0.611.
This is 61% approx.
Answer:
a. b=4
Step-by-step explanation:
From the attached triangle drawn below:
NL=20, LM=3b, 
Since we are told that:
The correct option is A.
Answer:
The length of s is 5.1 inches to the nearest tenth of an inch
Step-by-step explanation:
In Δ RST
∵ t is the opposite side to ∠T
∵ r is the opposite side to ∠R
∵ s is the opposite side to ∠S
→ To find s let us use the cosine rule
∴ s² = t² + r² - 2 × t × r × cos∠S
∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°
→ Substitute them in the rule above
∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)
∴ s² = 16.81 + 50.41 - 41.1677568
∴ s² = 26.0522432
→ Take √ for both sides
∴ s = 5.10413981
→ Round it to the nearest tenth
∴ s = 5.1 inches
∴ The length of s is 5.1 inches to the nearest tenth of an inch
