Answer:
4/5 of the cattle is left
Step-by-step explanation:
Given,
A farmer sells 2/5 of his cattle
Let "x" be the total number of cattle
Then,
sold = 2 / 5 x
Remaining = x - 2x / 5
remaining = 3x / 5
He gives 1/3 of the remainder to his son
son = 1 / 3 × 3x / 5
son = x / 5
Remaining = 3x / 5 - x / 5
Remaining = 4x / 5
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Have a great day
Mark brainliest
Thus 4/5 of the cattle is left
Choice A
(4m^5n^2/m^2n)^3
dividing exponents = subtraction
(4m^3n)^3
4^3 = 64
(m^3 )^3 = m^3x3 = m^9
64m^9n^3
342
x=5
72+72+18(5)+9+18 (5)+9=342
p-20