Answer:
Step-by-step explanation:
Subtract 2x
from both sides of the equation.
y=8−2x
x−y=2
Replace all occurrences of y
in x−y=2 with 8−2x
.
y=8−2x
x−(8−2x)=2
Simplify the left side.
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y=8−2x
3x−8=2
Solve for x
in the second equation.
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y=8−2x
x=103
Replace all occurrences of x
in y=8−2x with 103
.
y=8−2(103)
x=103
Simplify 8−2(103)
.
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y=43
x=103
The solution to the system of equations can be represented as a point.
(103,43)
9514 1404 393
Answer:
12 liters
Step-by-step explanation:
The kerosene usage is assumed to be jointly proportional to the number of stoves and the number of hours. That is ...
v = k·s·h . . . . . for s stoves running h hours
Then the value of k is ...
k = v/(sh) = (16 L)/(12·14) = 2/21 . . . . liters per stove-hour
Then the volume of kerosene required for 7 stoves and 18 hours is ...
v = (2/21)·s·h
v = (2/21)(7)(18) = 12 . . . liters
Answer:
YEAAAAAAAAAAAAAAAAAAAA
Step-by-step explanation:
We know that the volume is: V = 1 gallon = 231 in³
Also : r = 3 in.
The volume of a cylinder: V = r² π h
231 = 3³ · 3.14 · h
231 = 9 · 3.14 · h
231 = 28.26 h
h = 231 : 28.26
h = 8.17 ≈ 8 in
Answer: C) 8 in.
