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4 years ago

Y = x square - 4 can you answer please

Mathematics

2 answers:

liberstina [14]4 years ago

7 0

Answer:

there ya go, I hope this helped

Ber [7]4 years ago

3 0

Answer:

In the attachments, hope this helps

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Help please I will give brainlist

pogonyaev

Answer:

B y+8 = 2(x-4)

Step-by-step explanation:

perpendicular slope is a negative reciprocal of the x

which is 2x

then use the formula

y-y1 = m(x-x1)

y + 8 = 2(x-4)

7 0

2 years ago

A rectangle is a rhombus.

Soloha48 [4]

False. It’s a quadrilateral.

4 0

3 years ago

Read 2 more answers

If two or more polygons are congruent, which statement must be true about the polygons? Read all of the choices before deciding.

Lisa [10]

Pairs of corresponding angles have the same measure.

3 0

4 years ago

A survey showed that 77% of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 22 adults are

Sveta_85 [38]

Answer:

The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

Step-by-step explanation:

A survey showed that 77% of adults need correction for their eyesight.

If 22 adults are randomly selected, find the probability that no more than more than 11 of them need correction for their eyesight.

n =22

p = 0.77

q = 1-p = 1- 0.77=0.23

We are supposed to find $P(x\leq 11)$

$P(x\leq 11)=P(x=1)+P(x=2)+P(x=3)+.....+P(x=11)$

Formula : $P(x=r)=^nC_r p^r q^{n-r}$

$P(x\leq 11)=^{22}C_1 (0.77)^1 (0.23)^{22-1}+^{22}C_2 (0.77)^2 (0.23)^{22-2}+^{22}C_3 (0.77)^1 (0.23)^{22-3}+.....+^{22}C_{11} (0.77)^1 (0.23)^{22-11}$

Using calculator

$P(x\leq 11)=0.00512$

So, The probability that no more than more than 11 of them need correction for their eyesight is 0.00512

No, 11 is not a significantly low low number of adults requiring eyesight correction .

3 0

3 years ago

Express each expression as a single logarithm.

andreev551 [17]

Answer:

1. 6

2. 23

Step-by-step explanation:

logx+1 ( x^2 + 2x + 1)^3

= 3logx+1 ( x^2 + 2x + 1)

= 3 logx+1 (x + 1)^2

= 6 logx+1 (x + 1) Now the logx+1 x+1 = 1 so

The answer is 6.

log11 11^23

= 23 log11 11

As in question 1 log11 11 = 1

So the answer is 23.

8 0

3 years ago