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3 years ago

8

Lisa Company uses the periodic inventory system to account for inventories. Information related to Lisa Company's inventory at O

ctober 31 is given below:
October
1
Beginning inventory
390 units x $9.80 = $3,822
8
Purchase
790 units x $10.50 = 8,295
16
Purchase
590 units x $10.60 = 6,254
24
Purchase
195 units x $11.60 = 2,262
Total units and cost
1,965 units $20,633

1 answer:

scZoUnD [109]3 years ago

6 0

Answer:

The value of ending inventory will be items of latest purchase.

Step-by-step explanation:

Given that,

Lisa Company uses the periodic inventory system to account for inventories.

Information related to Lisa Company's inventory at October 31 is given,

Suppose, find the value of ending inventory using the FIFO cost assumption if 500 units remains on hand at october 31

We need to calculate the value of ending inventory

Using FIFO method

$value\ of\ ending\ inventory =305\ units\times\$10.6+195\ units\times\$11.60$

$value\ of\ ending\ inventory = 3233+2262$

$value\ of\ ending\ inventory =\$5495$

Hence, The value of ending inventory will be items of latest purchase.

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Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Ass

zimovet [89]

Answer:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

$X \sim N(14.4,1.1)$

Where $\mu=14.4$ and $\sigma=1.1$

For this part we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.05$ (a)

$P(X$ (b)

We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64

Using this value we can set up the following equation:

$P(X$

$P(z$

And we have:

$z=1.64$

And if we solve for a we got

$a=14.4 +1.64*1.1=16.204$

The 95th percentile of the hip breadth of adult men is 16.2 inches.

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2 years ago

What is the difference?

worty [1.4K]

Answer:

4th option

Step-by-step explanation:

Given

$\frac{x}{x^2+3x+2}$ - $\frac{1}{(x+2)(x+1)}$ ← expand denominator using FOIL

= $\frac{x}{x^2+3x+2}$ - $\frac{1}{x^2+3x+2}$

Since the denominators are common, then subtract the numerators

= $\frac{x-1}{x^2+3x+2}$

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2 years ago

Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20

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Answer:

$P_{20} = 20$ --- 20th percentile

$P_{25} = 21.75$ --- 25th percentile

$P_{65} = 27.85$ --- 65th percentile

$P_{75} = 29.5$ --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

$P_{20} = 20 * \frac{N +1}{100}$

$P_{20} = 20 * \frac{8 +1}{100}$

$P_{20} = 20 * \frac{9}{100}$

$P_{20} = \frac{20 * 9}{100}$

$P_{20} = \frac{180}{100}$

$P_{20} = 1.8th\ item$

This is then calculated as:

$P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)$

$P_{20} = 16 + 0.8*(21 - 16)$

$P_{20} = 16 + 0.8*5$

$P_{20} = 16 + 4$

$P_{20} = 20$

Solving (b): The 25th percentile

This is calculated as:

$P_{25} = 25 * \frac{N +1}{100}$

$P_{25} = 25 * \frac{8 +1}{100}$

$P_{25} = 25 * \frac{9}{100}$

$P_{25} = \frac{25 * 9}{100}$

$P_{25} = \frac{225}{100}$

$P_{25} = 2.25\ th$

This is then calculated as:

$P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)$

$P_{25} = 21 + 0.25(24-21)$

$P_{25} = 21 + 0.25(3)$

$P_{25} = 21 + 0.75$

$P_{25} = 21.75$

Solving (c): The 65th percentile

This is calculated as:

$P_{65} = 65 * \frac{N +1}{100}$

$P_{65} = 65 * \frac{8 +1}{100}$

$P_{65} = 65 * \frac{9}{100}$

$P_{65} = \frac{65 * 9}{100}$

$P_{65} = \frac{585}{100}$

$P_{65} = 5.85\th$

This is then calculated as:

$P_{65} = 5th + 0.85(6th - 5th)$

$P_{65} = 27 + 0.85(28 - 27)$

$P_{65} = 27 + 0.85(1)$

$P_{65} = 27 + 0.85$

$P_{65} = 27.85$

Solving (d): The 75th percentile

This is calculated as:

$P_{75} = 75 * \frac{N +1}{100}$

$P_{75} = 75 * \frac{8 +1}{100}$

$P_{75} = 75 * \frac{9}{100}$

$P_{75} = \frac{75 * 9}{100}$

$P_{75} = \frac{675}{100}$

$P_{75} = 6.75th$

This is then calculated as:

$P_{75} = 6th + 0.75(7th - 6th)$

$P_{75} = 28 + 0.75(30- 28)$

$P_{75} = 28 + 0.75(2)$

$P_{75} = 28 + 1.5$

$P_{75} = 29.5$

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3 years ago

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BlackZzzverrR [31]

Answer:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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