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3 years ago

Divide each polynomial by a monomial. (4x^4+2x^3+2x^2)÷10x

Mathematics

1 answer:

Colt1911 [192]3 years ago

3 0

Answer:

2/5x³ + 1/5x² + 1/5x

Step-by-step explanation:

You have to divide each term in the polynomial by the monomial.

(4x⁴ + 2x³ + 2x²)/10x

2/5x³ + 1/5x² + 1/5x

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2 years ago

A= [2, 3; 2, 1], B=[3; 5]. Find AB & BA if possible

oksano4ka [1.4K]

Answer:

The value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$ and it's not possible to multiply BA.

Step-by-step explanation:

Consider the provided matrices.

$A=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right]$ , $B=\left[\begin{array}{ccc}3\\5\end{array}\right]$

Two matrices can be multiplied if and only if first matrix has an order m × n and second matrix has an order n × v.

Multiply AB

Matrix A has order 2 × 2 and matrix B has order 2 × 1. So according to rule we can multiply both the matrix as shown:

$AB=\left[\begin{array}{ccc}2&3\\2&1\end{array}\right] \left[\begin{array}{ccc}3\\5\end{array}\right]$

$AB=\left[\begin{array}{ccc}2\times 3+3\times 5\\2\times 3+1\times 5\end{array}\right]$

$AB=\left[\begin{array}{ccc}6+15\\6+5\end{array}\right]$

$AB=\left[\begin{array}{ccc}21\\11\end{array}\right]$

Hence, the value of AB is $\left[\begin{array}{ccc}21\\11\end{array}\right]$

Now calculate the value of BA as shown:

Multiply BA

Matrix B has order 2 × 1 and matrix A has order 2 × 2. So according to rule we cannot multiply both the matrix.

We can multiply two matrix if first matrix has an order m × n and second matrix has an order n × v.

That means number of column of first matrix should be equal to the number of rows of second matrix.

Hence, it's not possible to multiply BA.

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3 years ago

What value of x is in the solution set of 2x – 3 > 11 – 5x?

Alekssandra [29.7K]

$2x - 3 \ \textgreater \ 11- 5x\\
7x\ \textgreater \ 14\\
x\ \textgreater \ 2$

4

3 0

3 years ago

Read 2 more answers