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Viefleur [7K]
3 years ago
15

There are more answers please help

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

No you type the numbers press = and poof

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A 15 foot flagpole casts an 11 foot shadow. At the exact same time a 28 foot tree casts a shadow. Which proportion would correct
marishachu [46]
The longer an object, the longer the shadow they cast at a given time of the day and vice versa. This is called direct proportionality. At the same time,

If 15 foot flagpole ---- casts 11 foot shandow
    28 foot tree -------- casts ?? foot shadow

The proportion would therefore be:

Length of shadow cast by tree = (28/15)*11 = 20.533 foot.
8 0
3 years ago
How can you tell whether a counting problem is a permutation or combination problem? Give examples to support your answer
dolphi86 [110]

Answer:

Step-by-step explanation:

Permutation is the ways in which a fixed group or members that can be arranged or ordered and combinations are used when a smaller group has to be chosen from a larger group.

Examples:

<u>Permutation: </u>How many unique combinations of the word MAHNOOR can be formed when the letters will be scrambled

2. In what order or arrangements five people can be seated in the front row?

The number of people are fixed, we have to find the order.

<u>Combination:</u> Choosing two cards from a deck of 52 cards. We are choosing a small group from a larger group of all cards.

2. Choosing 4 students from a class to take part in the competition.

The selection can be made in multiple ways ..

4 0
3 years ago
Read 2 more answers
Test the series for convergence or divergence (using ratio test)​
Triss [41]

Answer:

    \lim_{n \to \infty} U_n =0

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given series is an alternating series

∑(-1)^{n} \frac{n^{2} }{n^{3}+3 }

Let   U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }

By using Leibnitz's rule

   U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }

 U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}

Uₙ-Uₙ₋₁ <0

<u><em>Step(ii):-</em></u>

    \lim_{n \to \infty} U_n =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }

                       =  \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }

                    = =  \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }

                       =\frac{1}{infinite }

                     =0

    \lim_{n \to \infty} U_n =0

∴ Given series is converges

                       

                     

 

3 0
3 years ago
jayden had some money in his pocket.Then a friend loaned him $1.35.Now jayden has $3.75 in his pocket.
Rina8888 [55]

Answer:

If you were wondering how much he had to begin with, it would be $5.10.

Step-by-step explanation:

Hopefully this helps you :3

5 0
3 years ago
Find the hypotenuse of a right triangle with legs measuring 4 and 5ft
tangare [24]
The hypotenuse would be square root of 41
6 0
3 years ago
Read 2 more answers
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