Answer:
m∠FEH = 44°
m∠EHG = 64°
Step-by-step explanation:
1) The given information are;
The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°
Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°
Therefore, angle subtended by arc ∠HGF at the center = 88°
The angle subtended by arc ∠HGF at the circumference = m∠FEH
∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)
m∠FEH = 44°
2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°
The sum of angles in a quadrilateral = 360°
Therefore;
m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)
m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°
m∠EHG = 64°.
Answer:
t=5
Step-by-step explanation:
34+9.70t=82.50
-34 -34.00
9.70t=48.50
divide 9.70 from both sides
t=5
Answer:
It isn't a proportional relationship
Step-by-step explanation:
It's not a proportional relationship because you would have to divide both numbers on the chart by a number they both have in common and when you divide them and it doesn't equal 0 then it is not a proportional relationship.
Answer:
C. 60°
Step-by-step explanation:
The angles in a triangle add up to 180°.
You are given 60° and 60°.
Add them
60 + 60 = 120
Subtract 120 from 180.
180 - 120 = 60°
Answer:
Los lados de la lista cuadrada que le fabricaron miden 15 m
Step-by-step explanation:
Hola! Sabemos que la loseta tiene área cuadrada y que el área del cuadrado está dada por:
Ac = a²
Donde a es la medida de los lados del cuadrado.
Para hallar la medida de la lista cuadrada despejamos a aplicando raíz cuadrada a ambos miembros:
a = √(Ac)
a = √(225 m²)
a = 15 m
Los lados de la lista cuadrada que le fabricaron miden 15 m
and the mean value A is equal to zero.