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masya89 [10]
3 years ago
11

If f(x)=x^2+9x and g(x)=1/x, find f(g(-1)).

Mathematics
2 answers:
shtirl [24]3 years ago
8 0

Answer:

x=3

Step-by-step explanation:

x^2-9

bcos g(-1)=-1

f(g)=x^2+9(-1)=0

x^2-9=0

x^2=9

x=√9

x=3

Sergeeva-Olga [200]3 years ago
8 0
<h2><u><em>Answer:</em></u></h2><h2><u><em>dfgsdfgjfsdpogjpdisfiodfsgjdfgoipgdsfjiojgidfjiogdfjgdosfjoigpdjoigfddhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfk</em></u></h2><h2><u><em>Explanation:</em></u></h2><h2><u><em>dfgsdfgjfsdpogjpdisfiodfsgjdfgoipgdsfjiojgidfjiogdfjgdosfjoigpdjoigfddhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfk</em></u><em><u>dfgsdfgjfsdpogjpdisfiodfsgjdfgoipgdsfjiojgidfjiogdfjgdosfjoigpdjoigfddhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfkdhfguopaszghsdfpgbnhdfijpghsdjfkghdfsghupdssghujidghsdfjgkldfk</u></em></h2>

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Find the value of cos J rounded to the nearest hundredth, if necessary.
WARRIOR [948]

\green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}}

Find the value of cos J rounded to the nearest hundredth

\bold{ \red{\star{\blue{GIVEN }}}}

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\bold{\blue{\star{\red{TO \:  \: FIND}}}}

\cos(j)  =  ?

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

  1. PYTHAGORAS THEROM
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\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

<h2>FOR BASE:- </h2>

{h}^{2}  =  {p}^{2}  +  {b}^{2}

{13}^{2}  =  {12}^{2}  +  {x}^{2}  \\ 169 - 144 =  {x}^{2}  \\ 25 =  {x}^{2}  \\  \sqrt{25}  = x \\ 5 = x = base

<h2>NOW :- </h2>

\cos(j) =  \frac{ BASE}{HYPOTENUSE}

\cos(j)  =  \frac{5}{13}  \\  \cos(j)  = 0.34

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