Under T, the point (0,2) gets mapped to (3,0). T -1 (x, y)

Mathematics

2 answers:

Scilla [17]2 years ago

6 0

Answer:

(x-3,y+2)

Step-by-step explanation:

Stells [14]2 years ago

4 0

Answer: The correct option is

(B) $T^{-1}(x,y)=(x-3,y+2).$

Step-by-step explanation: Given that under T, the point (0,2) gets mapped to (3,0).

We are to find the expression for $T^{-1}(x,y).$

According to the given information, we have

$T(0,2)=(3,0)=(0+3,2-2)\\\\\Rightarrow T(x,y)=(x+3,y-2)\\\\\Rightarrow T^{-1}(x+3,y-2)=(x,y)\\\\\Rightarrow T^{-1}(x+3-3,y-2+2)=(x-3,y+2)\\\\\Rightarrow T^{-1}(x,y)=(x-3,y+2).$

Thus, the required expression is $T^{-1}(x,y)=(x-3,y+2).$

Option (B) is CORRECT.

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