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3 years ago

The area of the triangle below is 5.52 square feet. What is the length of the base?

Mathematics

1 answer:

pogonyaev3 years ago

8 0

Answer:

4.6 ft

Step-by-step explanation:

The formula for the area of a triangle is ...

A = 1/2bh

Fill in the given values and solve for the base.

5.52 = 1/2b(2.4)

5.52/1.2 = b = 4.6 . . . . divide by the coefficient of b

The base is 4.6 feet.

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Select the correct answer from each drop-down menu. ronald is buying a rectangular chest to store his carpentry tools. the heigh

shepuryov [24]

The function that represents the volume of the chest is 40.

What is a volume simple definition?

The amount of space occupied by a three-dimensional figure as measured in cubic units (as inches, quarts, or centimeters) cubic capacity.
The amount of a substance occupying a particular volume.

When the Area of rectangular chest:

A(x) = 20√x /3

⇒ Volume of chest = Base area x Height

Therefore:

(X + 6) × 20√x /3

(20x√x /3 ) + (20 × 6√x/3)

(20x√x /3 ) + (20 × 2 × 3√x/3)

(20x√x/3) + 40√x

Therefore, the correct answer for the drop-down menu is that the first blank is multiply and the second blank is 40.

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8 0

2 years ago

How many time greater is 7,000 than 700?

PIT_PIT [208]

700•10 is 7000 so
10 times

6 0

3 years ago

Read 2 more answers

Answer the question If you're right I'll MARK YOU BRAINLIEST!!

natka813 [3]

Answer:

$2x\sqrt{40x}-2x\sqrt{5}$

Step-by-step explanation:

$2x\sqrt{40x}-2x\sqrt{5}$ is found by first, siplifying the radicals in the parenthesis. $\sqrt{8x^{2} }$ can be simplified as $2x\sqrt{2}$ and $-2\sqrt{x}$ stays the same. Now we have to multiply these two by $\sqrt{5x}$ which then results in $2x\sqrt{40x}-2x\sqrt{5}$

4 0

3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

Step 1: Define

Identify

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

Step 2: Find Right-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

Step 3: Find Left-Side Limit

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$