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uranmaximum [27]
3 years ago
14

Find the sum. express your answer in simplest form 8m^2-6/n+3 + 9m^2-4/n+3

Mathematics
1 answer:
Alex787 [66]3 years ago
4 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following expressions shown in the problem above:

 (<span>8m^2-6/n+3) + (9m^2-4/n+3)

 2. As you can see, they have equal denominators, then you have:

 (</span><span>8m^2-6+ 9m^2-4)/(n+3)
</span><span>
 3. Therefore, when you sum, you have the following result:

 (17m</span>²-10)/(n+3)
<span>
 The answer is: </span> (17m²-10)/(n+3)<span>

 

 

 </span>
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X-(-27)=35-12 solving equation
irakobra [83]
-4 is the correct answer
35-12 =25
-4 - ( -27) = -4 + 27 =23
4 0
3 years ago
HELP ME!!!!!!!!!!!!!!!!!!!!111
Vlad1618 [11]

Answer:

-40

Step-by-step explanation:

(-40) divided by 5 is (-8)

4 0
3 years ago
Read 2 more answers
Workers have been down the street installing two blinking red lights in front of the fire station. The two lights are always tur
daser333 [38]

Answer:

After 88 seconds, they will blink together.

Step-by-step explanation:

Time after which the first light blinks = 8 seconds

Time after which the second light blinks = 22 seconds

Initially, both the lights blink together.

To find:

The time at which they will blink together again.

Solution:

Let us have a look at the time after which each light will blink.

First light will blink after:

8 s, 16 s, 24 s, 32 s, 40 s, 48 s, 56 s, 64 s, 72 s, 80 s, <em>88 s</em>, 96 s, 104 s, ......

Second light will blink after:

22 s, 44 s, 66 s, <em>88 s</em>, 110 s, .....

It can be seen that common time is 88 second, at which the both will blink together.

So, the answer is <em>88 s.</em>

<em></em>

This answer can also be computed by taking the LCM (Least Common Multiple) of both the numbers i.e. 8 and 22.

Using the factorization method:

8=\underline{2}\times 2\times 2

22=\underline{2}\times 11

Common is 2.

Therefore the LCM will be:

2\times 2\times2\times 11 = \bold{88}

So, the answer is <em>88 s.</em>

5 0
3 years ago
Greatest to least<br> 2/7, 1/4, 2/9
Stella [2.4K]

<u>1/3; 2/7; 2/9</u>

Lets find least common multiple

The least common multiple is 63

1/3 --> 21/63

2/7 --> 18/63

2/9 --> 14/63

As you can see I am correct, but I found the LCM by multiplying 1/3 by 21 to get to 63 and the numerator as well

7 0
3 years ago
What is reasonable first step that can be used to solve the equation 2(x+6)=3(x-4)+5?
blagie [28]

Answer:

Distribute 2 to (x + 6) and 3 to (x-4)

Step-by-step explanation:

8 0
3 years ago
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