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sveticcg [70]
3 years ago
8

Look at the following program and answer the question that follows it. 1 // This program displays my gross wages. 2 // I worked

40 hours and I make $20.00 per hour. 3 #include 4 using namespace std; 5 6 int main() 7 { 8 int hours; 9 double payRate, grossPay; 10 11 hours = 40; 12 payRate = 20.0; 13 grossPay = hours * payRate; 14 cout << "My gross pay is $" << grossPay << endl; 15 return 0; 16 } Which line(s) in this program cause output to be displayed on the screen?
Computers and Technology
1 answer:
viva [34]3 years ago
4 0

Answer:

The answer is "14 Line".

Explanation:

In the given C++ language code the main method defines a variable that is "hours, payRate, and grossPay". In which variable hours is an integer variable and payRate and grossPay is double type variable.

In hours and payRate variable, we assign a value that is "40 and 20.0" and the variable grossPay assign formula that calculates value and holds value in this variable. Then we use print (cout) function to print grossPay variable value.

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Output a table that show the cube of the numbers 1-15<br> (C++)
Rainbow [258]

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {    

   // variables declared and initialized  

   int num = 15, k, cube;    

   cout << " Cubes of numbers from 1 to 15 are shown below " << endl;    

   for( k = 1; k <= num; k++ )

   {

       // cube is calculated for each value of k and displayed

       cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

return 0;

}

 

OUTPUT

Cubes of numbers from 1 to 15 are shown below  

  1

  8

  27

  64

  125

  216

  343

  512

  729

  1000

  1331

  1728

  2197

  2744

  3375

Explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

   for( k = 1; k <= num; k++ )

   {

      cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

3 0
3 years ago
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