It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3
Answer:
The potential energy of the ball having 2kg mass would be
J
Step-by-step explanation:
I am assuming the ball has a mass of 2 kg, as you have not mentioned the mass of a ball.
Considering the formula for calculating the gravitational potential energy

As
kg
Acceleration of gravity = g = 9.8 
As the ball is on the height = h = 20 meters
So,

J
Therefore, the potential energy of the ball =
J
Keywords: potential energy, Gravitation potential energy
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Assuming your numbers are rounded to the nearest km, the minimum area will be ...
(5.5 km)·(10.5 km) = 57.75 km² . . . minimum
And the maximum area will be ...
(6.5 km)·(11.5 km) = 74.75 km² . . . maximum
_____
When a number is rounded to 6 km as the nearest km, its value may actually be anywhere in the range 6 km ± 0.5 km. If you really want to get technical about it, the ranges of possible dimensions are [5.5, 6.5) km and [10.5, 11.5) km, and the range of possible areas is [57.75, 74.75) km².
Answer:

Now we can find the second central moment with this formula:

And replacing we got:

And the variance is given by:
![Var(X) = E(X^2) - [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2)
And replacing we got:

And finally the deviation would be:

Step-by-step explanation:
We can define the random variable of interest X as the return from a stock and we know the following conditions:
represent the result if the economy improves
represent the result if we have a recession
We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

And replacing the data given we got:

Now we can find the second central moment with this formula:

And replacing we got:

And the variance is given by:
![Var(X) = E(X^2) - [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%20%5BE%28X%29%5D%5E2)
And replacing we got:

And finally the deviation would be:

The event by definition that covers the entire sample space of the experiment is;
<em><u>The number is even or less than 12</u></em>
We are given the numbers in the set as;
set {2, 3, 4,... 10}.
Now, the numbers in the set are even and odd numbers from 2 to 10 with 10 being the highest and 2 being the lowest.
Thus the event that covers this sample space is simply a set of numbers that are even or less than 12.
Read more about sample space of set at; brainly.com/question/18866708