Answer:
y=-3/16(x-8)^2+12
Step-by-step explanation:
Refer to the vertex form equation for a parabola:
y=a(x-h)^2+k where (h,k) is the vertex.
Therefore, we have y=a(x-8)^2+12 as our equation so far. If we plug in (16,0) we can find a:
0=a(16-8)^2+12
0=64a+12
-12=64a
-12/64=a
-3/16=a
Therefore, your final equation is y=-3/16(x-8)^2+12
Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is
.
The lateral surface area of the triangular pyramid is

cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
Answer:
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IF Factor x4−10x2+25
x4−10x2+25
=(x2−5)(x2−5)
Answer:
(x2−5)(x2−5)
IF simplify
x4−10x2+25
There are no like terms.
Answer:
=x4−10x2+25
Answer: a. gregory b. linus
step by step explanation: