Answer: 4004ways
Step-by-step explanation:
Total number of Students =15
Total number of students to be on the committee =5
Since two members are of the same major and must not be on the committee, then we are left with choosing 5 people from just 14 People after we eventually remove one from those two students with same majors.
Hence to select 5 people from 14 people, we use the combination formula 14C5.
From the two students with same major we also use the combination Formula in knowing the number of ways any of the two students can be chosen. To choose one from these two students, we use the combination Formula 2C1.
Hence, the total number of ways to choose the committee of 5 and ensuring the two students with same major aren't on the committee becomes:
= 14C5 * 2C1
= 2002 * 2
= 4004ways.
I think the best answer is 3 to 9 but thats not a answer so 3 to 6
Answer:
46
Step-by-step explanation:
To solve this, add.
28 + 18 = 46
Answer:
a = x² + 3x - 40
Step-by-step explanation:
a = l * w
a = (x - 5)(x + 8)
a = x(x + 8) - 5(x + 8)
a = (x² + 8x) + (- 5x - 40)
a = x² + 3x - 40
Answer:
Step-by-step explanation:
Given that according to the U.S. Census Bureau, the prob ability that a randomly selected household speaks only English at home is 0.81.
The probability that a randomly selected household speaks only Spanish at home is 0.12.
(a) the probability that a randomly selected household speaks only English or only Spanish at home
= 0.81+0.12 = 0.93
(since these two are disjoint sets)
(b) the probability that a randomly selected household speaks a language other than only English or only Spanish at home
= 1-0.93= 0.07 (remaining)
(c) the probability that a randomly selected household speaks a language other than only English at home
=1-0.81=0.19
(d) Can the probability that a randomly selected household speaks only Polish at home equal 0.08? Why or why not?
Polish alone can never exceed 1-(0.81+0.12) i.e. 0.70
At most it can take values as 0.7 only
So no is the answer.