This next phase is a Waxing Gibbous. Hope this helps!
Answer:
d. pxp +2pq
Explanation:
The formula for genotype frequency for a population in Hardy-Weinburg equilibrium is as under:
p² + 2pq + q² = 1
where, p = dominant allele
q = recessive allele
Here,
p² represents frequency of homozygous dominant genotype
2pq represents frequency of heterozygous genotype
q² represents frequency of homozygous recessive genotype
Also, although the genotypes p² & 2pq are different from each other yet phenotypically they both will collectively produce dominant trait i.e. free ear lobes not attached earlobes. So the term "p² + 2pq or pxp + 2pq" represents the frequency of the individuals who show the dominant phenotype in this particular population. Dominant phenotype will comprise 75% of the population.
5% of $20 is $1; 5% off $20 is $19
<u>Answer:</u>
A mating of two people of medium height (where three genes control height): AaBbCc x AaBbCc produce <u>Seven</u> distinct phenotypes determined by the number of genes inherited.
Option: (D)
<u>Explanation:</u>
- Traits are the characters that we observe. When the parents AaBbCc and AaBbCc are crossed then AABBCC and aabbcc are two different dominant and recessive genomes seen in the offspring.
- Offspring with AABBCC will be height whereas aabbcc will be dwarf. There will be offspring with different heights depending upon the dominant and recessive gene present in them.
- Another genome produced are AABBCc/AaBBCC/AABbCC, next will have four dominant and 2 recessive, next will have 3 dominant and 3 recessive AaBbCc, next will have 2 dominant and 4 recessive, one dominant and five recessive. All together offspring produced will be 64
Salt acid base or just an acid
