x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
In general 
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
Learn more about maximum of a function here:
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I'm pretty sure he would be 5 ft 3 in. tall.
7 / 33 + 13 / 27
7 / 46 / 27
Multiply them all to get... 8,694
Answer:
Step-by-step explanation: the best way to get this answer is by using a scientific calculator fx-991es plus I recommend
Let's go manual for now.
Let's covert pi/4 to angle
1⁰ =π/180
1 radian =180/π
Therefore π/4 × 180/π
∅ =45⁰
Sin-¹(tan 45⁰)
Tan 45⁰= 1
Sin-¹ (1) = 90⁰. Press { sin,-¹ (1) } on your calculator
Sin-¹ (tan pi/4) = 90⁰
Answer:
Step-by-step explanation:
We have to use the slope formula: m = slope
(x1, y1) = coordinates of the first point in the line
(x2, y2) = coordinates of the second point in the line
Here, we'll plug into our given points to give; 
Solving this, we get, 
, but we're not done, as this fraction can be reduced.
Diving both sides of the fraction by 2, we get our final answer of .
