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Arturiano [62]
3 years ago
10

The volume of the cylinder is 144 Pi cubic yards. Of h, the height of the cylinder is 4, what is r, the radius of the base?

Mathematics
1 answer:
soldi70 [24.7K]3 years ago
7 0

Answer:

6 yd (Answer D)

Step-by-step explanation:

The formula for the volume of a cylinder of radius r and height h is

V = πr²h.

Here, this V = πr²h equals 144π yd³.

We must solve πr²h =  144π yd³ for r with the constraint that h = 4 yd.

Replacing h with 4 yd:

πr²(4 yd) =  144π yd³

Dividing both sides by π, we get:

4r² yd = 144 yd³

                                       144 yd³

Solving for r²:         r² = -------------- = 36 yd²

                                         4 yd

Taking the square root of both sides, we get r = 6 yd   (Answer D)

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1)   x=\dfrac12

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3)  see below

4)  A:  0 = 1

Step-by-step explanation:

<u>Question 1</u>

15-0.5(4x-2)+4x=17

\implies 15-2x+1+4x=17

\implies 2x+16=17

\implies 2x=1

\implies x=\dfrac12

<u>Question 2</u>

\textsf{rearrange} \ n=m+1 :

\implies -m=-n+1

\textsf{add equations} \ -m=-n+1 \ \textsf{and} \ m=2n+2:\\

\implies0=n+3

\implies n=-3

\textsf{substitute} \ \ n=-3 \ \ \textsf{into} \ \ m=n-1:

\implies m=-3-1

\implies m=-4

<u>Question 3</u>

subtract the second equation from the first

divide both sides by -4

substitute found value for y into first equation

solve for x

<u>Question 4</u>

3j=k

k=3j+1

\textsf{rearrange} \ 3j=k :

\implies -k=-3j

\textsf{add equations}\  -k=-3j \ \ \textsf{and}\ \ k=3j+1:

\implies 0=1

Solution = A

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