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weeeeeb [17]
3 years ago
13

Write a program that reads the input.txt file character by character and writes the content of the input file to output.txt with

capitalize each word (it means upper case the first letter of a word and lowercase remaining letters of the word)
Computers and Technology
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Answer:

def case_convertfile( file_name):

    with open(" new_file","x") as file:

         file.close( )

    with open("file_name", "r") as txt_file:

     while True:

            word = txt_file.readline( )

            word_split= word.split(" ")

            for word in word_split:

                  upper_case = word.uppercase( )

                  file= open("new_file","w+")

                  file= open("new_file","a+")

                  file.write(upper_case)

     txt_file.close( )

     file.close( )

Explanation:

This python function would open an existing file with read privilege and a new file with write and append privileges read and capitalize the content of the old file and store it in the new file.

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slava [35]

Answer:

-checking social media networks during working hours

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Explanation:

they are all correct on edg.

8 0
3 years ago
Read 2 more answers
What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r;
ycow [4]

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

The function is defined as: myMathFunction(int a, int r, int counter)

It initially gets the following as its input from the main method

a= 1; r = 2; counter = 0

Its operation goes thus:

val = a*r; 1 * 2 = 2

Print val; Prints 2

if (counter > 4) { System.out.print("End"); } : Not true

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 2; r = 2; counter = 1

val = a*r; 2 * 2 = 4

Print val; Prints 4

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 4; r = 2; counter = 2

val = a*r; 4 * 2 = 8

Print val; Prints 8

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

val = a*r; 8 * 2 = 16

Print val; Prints 16

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 16; r = 2; counter = 4

val = a*r; 16 * 2 = 32

Print val; Prints 32

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 32; r = 2; counter = 5

val = a*r; 32 * 2 = 64

Print val; Prints 64

if (counter > 4) { System.out.print("End"); } : True

<em>This prints "End"</em>

So; the output of the program is:

2 4 8 16 32 64 End

3 0
3 years ago
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nlexa [21]

Answer:

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8 0
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A buggati or however u spell it


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On an LG phone, will a factory reset stop a message from sending/cancel a message? ​
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Answer:

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