What do the last two steps in the cyclical design process most likely involve
1 answer:
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Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header file.
int main() //defining main method
{
char i,j; //defining variable
for (i='a'; i<='e'; i++) //outer loop for column
{
for (j='a'; j<='e'; j++) //inner loop for row
{
printf("%c%c\n",i,j); //print value
}
}
return 0;
}
Output:
image.
Explanation:
- In the above C language program, firstly a header file is included. Then the main method is defined in this, a method contains a char variable that is "i and j". This variable is used in for loop, that is used to print the pattern.
- To print the following patter two for loop is used the outer loop is used for print columns and the inner loop prints row.
- In C language to print character, we use "%c" inside a loop print function is used, that prints characters.
Answer:
Step by step explanation along with code and output is provided below
Explanation:
#include<iostream>
using namespace std;
// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three
void print_seconds(int hours, int mints, int seconds)
{
int total_seconds= hours*3600 + mints*60 + seconds;
cout<<"Total seconds are: "<<total_seconds<<endl;
}
// test code
// user inputs hours, minutes and seconds and can also leave any of them by entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.
int main()
{
int h,m,s;
cout<<"enter hours if any or enter 0"<<endl;
cin>>h;
cout<<"enter mints if any or enter 0"<<endl;
cin>>m;
cout<<"enter seconds if any or enter 0"<<endl;
cin>>s;
print_seconds(h,m,s);
return 0;
}
Output:
enter hours if any or enter 0
2
enter mints if any or enter 0
25
enter seconds if any or enter 0
10
Total seconds are: 8710
