A) The alkali metal atoms forms a +1 ion, while the alkaline eaeth metal atom forms a +2 ion.
The correct answers about rusting, air pollution and products of water with rock are:
Option A. oxidation
Option D. Pollutants mix with air and water to make acid rain.
Option B. clay minerals and calcium carbonate
<h3>What is rusting?</h3>
Rusting is the process by which a metal especially reacts with oxygen in the atmosphere and water vapor to form a hydrated oxide of the metal known as hydrated iron (iii) oxide. This is known as rust.
The process is an oxidation process; option A.
<h3>How does air pollution impact chemical weathering?</h3>
Air pollution is the presence of substances in air known as pollutants which makes the air impure.
Air pollution impact chemical weathering as the pollutants mix with air and water to make acid rain which weathers rocks; option D.
<h3>What products are produced when water reacts with sodium in rocks?</h3>
The reaction of water with sodium in rocks result in the formation of clay minerals and calcium carbonate also as limestone, marble or chalk; option B.
In conclusion, the presence of pollutants in air results in acid rain and hence rock weathering.
Learn more rock weathering at: brainly.com/question/2341950
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Answer:
Compound
Explanation:
We want to know if it's a compound or a mixture.
An example of a mixture is salt water: you can heat it hot enough to boil off the water, leaving only the salt. This is a physical change, which is how you know it's a mixture.
Something like gold is a compound: if you heat it, or hit it, you'll still only have gold. You can only break it down by chemical means, which is how you know it's a compound.
Answer:
6.022 x 10²³; it is a conversion factor between moles and number of particles
Explanation:
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
For example,
18 g of water = 1 mole = 6.022 × 10²³ molecules of water
1.008 g of hydrogen = 1 mole of hydrogen = 6.022 × 10²³ atoms of hydrogen
238 g of uranium = 1 mole of uranium = 6.022 × 10²³ atoms of uranium
By taking ions:
62 g of NO⁻₃ = 1 mole of NO⁻₃ = 6.022 × 10²³ ions of NO⁻₃
96 g of SO₄²⁻ = 1 mole of SO₄²⁻ = 6.022 × 10²³ ions of SO₄²⁻
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,
N₂ + H₂ + 3O₂ --> 2HNO₃
The net enthalpy of formation of nitric acid is calculated by,
Hrxn = Hproduct - Hreactant
Since all the reactants are in their elemental forms, the simplified equation would be,
Hrxn = Hproduct
Substituting,
Hrxn = (-186.81 kJ/mol)(2 mols)
<em>Answer: -372.42 kJ</em>
