Answer:
0.016M
Explanation:
First we find the mole of AgNO3 by using the formula mass/molar mass..
Then we find molarity by the formula mole/volume...
I hope you get this..
Then we all die because the sun would blow up the earth.
The total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.
HOW TO CALCULATE NUMBER OF ATOMS:
- The number of atoms in a substance can be calculated by multiplying the number of moles in that substance by Avogadro's number as follows:
- no. of atoms = no. of moles × 6.02 × 10²³ mol-¹
- The number of moles in 7.10g of Cl is calculated as follows:
no. of moles = mass ÷ molar mass
no. of moles = 7.10g ÷ 35.5g/mol
no. of moles = 0.2mol
no of atoms = 0.2mol × 6.02 × 10²³
no. of atoms = 1.204 × 10²³atoms.
- Therefore, the total number of atoms in 7.10g of chlorine is 1.204 × 10²³atoms.
Learn more: brainly.com/question/15488332?referrer=searchResults
Toxicants generally follow the Law of Diffusion , moving from areas of high concentration to areas of lower concentration.
<h3><u>What are Toxicants ?</u></h3>
Any hazardous chemical is a toxicant. Both naturally occurring and artificial toxicants have the potential to be harmful. A toxin, in contrast, is a poison created spontaneously by an organism (e.g. plant, animal, insect). The many toxicant categories may be present in the air, land, water, or food.
A substance is toxic if it has the potential to be harmful or have negative effects on health. Chemicals like polychlorinated biphenyls (PCBs) and dioxin, which are present at some hazardous waste sites, often cause people to worry.
<h3><u>What is the Law of Diffusion ?</u></h3>
Graham's law of diffusion states that the ratio of the diffusion rate of two gases is the same as the ratio of the square root of the molar mass of the gases.
To view more questions about Toxicants, refer to: brainly.com/question/5896648
#SPJ4
<span>Use the van't Hoff equation:
ln
(
K2
K1
)
=
Δ
HÂş
R
(
1
T1
â’
1
T2
)
ln
(
K2
7.6*10^-3
)
=
-14,200 J
8.314
(
1
298
â’
1
333
)
ln
(
K2
7.6*10^-3
)
=
â’
1708
(
0.00035
)
ln
(
K2
0.0076
)
=
â’
0.598
Apply log rule
a
=
log
b
b
a
-0.598 =
ln
(
e
â’
0.598
)
=
ln
(
1
e
0.598
)
Multiply both sides with e^0.598
K
2
e
0.598
= 0.0076
K
e
0.598
e
0.598
=
0.0076
e
0.598
K
2
=
0.0076
e
0.598
=
4.2
â‹…
10
â’
3
K2
=
4.2
â‹…
10
â’
3</span>