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zimovet [89]
1 year ago
5

select the correct answer from each drop down menu how do you the freezing point and boiling point of a solution compare with th

ose of us pure solvent? The freezing point of the solution is ___ and the boiling point is _____ than that of its pure solvent.
Chemistry
1 answer:
miss Akunina [59]1 year ago
4 0

Explanation:

select the correct answer from each drp down

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A substance that dissolves another substance is a _____________________
Scorpion4ik [409]

Answer:

b it is easy its b

Explanation:

7 0
3 years ago
Read 2 more answers
Which statements describe phase changes? Check all that apply. Particles in a liquid need to move more slowly in order to freeze
Kipish [7]

Answer: Statements (A), and (C) are correct.

Explanation:

The statements that are true are as follows.

  • Particles in a liquid need to move more slowly in order to freeze.

When a liquid freezes the molecules get attracted towards each other. This attraction of particles occurs slowly. Hence, this statement is true.

  • Attractive forces between the particles in a liquid are broken when a liquid boils.

When temperature is raised, the molecules in a liquid gains kinetic energy and start to move quickly in random directions. As a result, liquid state changes to gaseous state. Hence, this statement is true.

If the attractive force between gas molecules have to be increased, they should be moving slower instead because moving faster does not help attracting molecules together.

Hence, the statement particles in gas move fast enough to make more attractive forces when the gas condenses is not true.


4 0
3 years ago
Read 2 more answers
672cm x 11cm / 6.3cm^3
bezimeni [28]
117 333.333 m-1 your welco
5 0
3 years ago
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Hydrogen iodide, HI, is formed in an equilibrium reaction when gaseous hydrogen and iodine gas are heated together. If 20.0 g of
Kaylis [27]

Answer: D. 19.9 g hydrogen remains.

Explanation:

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

a) moles of H_2

\text{Number of moles}=\frac{20.0g}{2g/mol}=10.0moles

b) moles of I_2

\text{Number of moles}=\frac{20.0g}{254g/mol}=0.0787moles

H_2(g)+I_2(g)\rightarrow 2HI(g)

According to stoichiometry :

1 mole of I_2 require 1 mole of H_2

Thus 0.0787 moles of l_2 require=\frac{1}{1}\times 0.0787=0.0787moles of H_2

Thus l_2 is the limiting reagent as it limits the formation of product and H_2 acts as the excess reagent. (10.0-0.0787)= 9.92 moles of H_2are left unreacted.

Mass of H_2=moles\times {\text {Molar mass}}=9.92moles\times 2.01g/mol=19.9g

Thus 19.9 g of H_2 remains unreacted.

5 0
2 years ago
What is the relative rate of effusion for hydrogen iodide (128 g/mol) compared to gaseous hydrochloric acid (36.5 g/mol)
MArishka [77]

This question is hard but I found the answer from merit nation

8 0
3 years ago
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