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trasher [3.6K]
3 years ago
11

Simon drove for 2 1/2 hours to get from his house to the beach. Simon averaged 55 miles per hour on the trip. What is the distan

ce from Simon's house to the beach?
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

137.5 Miles

Step-by-step explanation:

Time driven=5/2 hours

Miles per hour=55

55 times 5/2= 137.5 miles

You might be interested in
the midpoint of a horizontal line segment is at x=1 if the length of the line segment is 10.5. what absolute value equation coul
egoroff_w [7]

Answer: -4.25 ≤ x ≤ 6.25

Step-by-step explanation:

The midpoint of a segment is located at the same distance of each of the endpoints of the segment.

The midpoint is at x = 1.

The length of the segment is 10.5, if we divide it by two we have:

10.5/2 = 5.25

Now, if we want the endpoints to be at the same distance of the midpoint, then the endpoints will be:

Xmax = midpoint + 5.25

Xmin = midpoint - 5.25

Then the extremes are:

Xmax = 1 + 5.25 = 6.25

Xmin = 1 - 5.25 = -4.25

Then this segment can be written as:

Xmin ≤ x ≤ Xmax

-4.25 ≤ x ≤ 6.25

8 0
3 years ago
Can someone help explain this?
bogdanovich [222]
The mode is whichever one has the most so the mode would be 7. And the range is the highest number to the lowest. So 9-4 which is 5
3 0
2 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
Read 2 more answers
Quadrilateral PQRS is a rectangle.<br><br> Find the measure of _PTQ.
hichkok12 [17]

Answer:

∠PTQ = 124°

Step-by-step explanation:

∠QPT = 90° - 62° = 28°

∠PQT = 28°

∠PTQ = 180° - 28° - 28° = 124°

6 0
3 years ago
Find the possibility of rolling even numbers three times, using a six-side die number from 1 to 6
seraphim [82]

Answer:

\frac{1}{8}

Step-by-step explanation:

Number of sides of die = 6

Number of sides with even numbers = 3

P( rolling an even number 1 time) = \frac{3}{6} = \frac{1}{2}

P(rolling even number 3 times) = \frac{1}{2} x \frac{1}{2}  x \frac{1}{2} = \frac{1}{8}

5 0
3 years ago
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