Question

What is the slope of a line perpendicular to the line whose equation is 15x+18y=270. Fully simplify your answer.

Answer 1

Answer:

6/5

Step by step explanation:

Here we are provided with a equation which is ,

$\longrightarrow 15x + 18y = 270$

And we are interested in finding the slope of the line which is perpendicular to the given line. We may rewrite the equation as ,

$\longrightarrow 18y = -15x +270$

$\longrightarrow y =\dfrac{-15x+270}{18}$

$\longrightarrow y =\dfrac{-15}{18}x +\dfrac{270}{8}$

$\longrightarrow y =\dfrac{-5}{6}x +\dfrac{135}{4}$

Recall the slope intercept form of the line which is y = mx + c .On comparing to which we get ,

$\longrightarrow m =\dfrac{-5}{6}$

Again , recall that product of slopes of two perpendicular lines is -1. So that ,

$\longrightarrow m_{\perp} =-\bigg(\dfrac{1}{m}\bigg)$

Hence ,

$\longrightarrow\underline{\underline{ m_{\perp}= \dfrac{6}{5}}}$

And we are done !

Answer 2

Step-by-step explanation:

hope it's helpful thanks