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PilotLPTM [1.2K]
2 years ago
14

What is the slope of a line perpendicular to the line whose equation is 15x+18y=270. Fully simplify your answer.

Mathematics
2 answers:
In-s [12.5K]2 years ago
6 0

Answer:

6/5

Step by step explanation:

Here we are provided with a equation which is ,

\longrightarrow 15x + 18y = 270

And we are interested in finding the slope of the line which is perpendicular to the given line. We may rewrite the equation as ,

\longrightarrow 18y = -15x +270\\

\longrightarrow y =\dfrac{-15x+270}{18}\\

\longrightarrow y =\dfrac{-15}{18}x +\dfrac{270}{8}\\

\longrightarrow y =\dfrac{-5}{6}x +\dfrac{135}{4}

Recall the slope intercept form of the line which is <u>y</u><u> </u><u>=</u><u> </u><u>mx</u><u> </u><u>+</u><u> </u><u>c</u><u> </u>.On comparing to which we get ,

\longrightarrow m =\dfrac{-5}{6}

Again , recall that product of slopes of two perpendicular lines is -1. So that ,

\longrightarrow m_{\perp} =-\bigg(\dfrac{1}{m}\bigg)

Hence ,

\longrightarrow\underline{\underline{ m_{\perp}= \dfrac{6}{5}}}

And we are done !

QveST [7]2 years ago
6 0

Step-by-step explanation:

hope it's helpful thanks

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Answer:

y' = 9x^2 + 8x^-5

Step-by-step explanation:

General Principle

y' = ax^b

y' = a*b * x^(b-1)

Solution

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3x^3 = 9x^2

-2x^-4  = -2*-4 x ^(-4 - 1)

-2x^-4 = 8 x ^-5

Answer

y' = 9x^2 + 8x^-5

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A teacher records the number of students present in her 1st period class each day. This count is a ___________ random variable.
blagie [28]

This count is a discrete random variable (option A).

<h3>What is a discrete random variable?</h3>

A discrete random variable is a variable that contains integers that can only be a limited number of possible values.  A discrete random variable is can contain only a finite set of numbers .

An example of discrete random variable is the number of students in the first period class. It is impossible for the number of students in the class to go on indefinitely.

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To learn more about discrete data, please check: brainly.com/question/22916429

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7 0
2 years ago
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Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today
Nataly_w [17]

Answer:

m = 10\sqrt 3

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Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

\sin(60) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60) = \frac{m}{20}

Make m ths subject

m = 20 * \sin(60)

\sin(60) =\frac{\sqrt 3}{2}

So, we have:

m = 20 *\frac{\sqrt 3}{2}

m = 10\sqrt 3

Considering the given angle again, we have:

\cos(60) = \frac{Adjacent}{Hypotenuse}

This gives:

\cos(60) = \frac{n}{20}

Make n the subject

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So, we have:

n = 20 *\frac{1}{2}

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2 years ago
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