A) -3√288=-3√(144*2)=-3√144<span>√2=-3*12</span><span>√2=-36</span><span>√2
b) </span>5√320=5<span>√(64*5)=</span>5<span>√64</span><span>√5=5*8</span><span>√5=40</span><span>√5</span>
If there is 8 boys then there is 12 girls because 2x4=8 boys so 3x4=12 girls.
When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:
tangent line^2 = 8.45 * (8.45 + x)
13.5^2 = 71.4025 + 8.45 x
182.25 -71.4025 = 8.45x
8.45 x = 110.8475
x = 13.1180473373
x = 13.1 (rounded)
Source:
1728.com/circangl.htm
Answer:
Step-by-step explanation:
m∠1 = 2x and m∠2 = -3x+235
angle 1 and angle 2 are supplementary angle so they add up to 180°
m∠1 +m∠2 = 180°
2x -3x+235 = 180°
-x = 180-235
x=35
m∠1 = 2x = 2*35 = 70°
m∠2 = -3x+235 = -3*35 +235 = 235-105 = 130°
Answer:
The probability that both the students selected are of the same gender is 0.25.
Step-by-step explanation:
Let <em>X</em> = number of students selected of the same gender.
The probability of selecting a student of a particular gender is,
P (X) = <em>p</em> = 0.50.
The number of students selected is, <em>n</em> = 2.
The random variable follows a Binomial distribution.
The probability of a binomial distribution is computed using the formula:

Compute the probability that both the students selected are of the same gender as follows:
P (Both boys) = P (Both girls) = P (X = 2)

Thus, the probability that both the students selected are of the same gender is 0.25.