The complete question is
A fence must be built to enclose a rectangular area of 5000ft^2. Fencing material costs $1 per foot for the two sides facing north and south and 2$ per foot for the other two sides. Find the cost of the least expensive fence.
Answer:
Total cost will be $400
Step-by-step explanation:
Let x = be other side
y = north and south side
Area = x*y = 5000
Perimeter of the rectangle = 2x + 2y
cost of fencing = 2(1)*5000/x + 2*2x
= 10000/x + 4x
now to get the least we will take the derivative of this
C'(x) = 10000(-1/x^2) + 4 =0
x^2 = 2500
x= 50ft cost = 2*$2*50 = $200
y= 100ft cost = 2*$1*100 = $200
Total cost = $400
Answer:
3/2
Step-by-step explanation:
We can use the slope formula to find the slope of the line
m = ( y2-y1)/(x2-x1)
Using the points (0,-4) and (2,-1)
m = ( -1 - -4)/( 2 - 0)
= (-1+4)/ (2 -0)
= 3/2
Answer:
y=x
Step-by-step explanation:
y=12
Answer: 4/3
Step-by-step explanation:
What are the corresponding sides?
4 and 3
8 and 6
9 and 6.75
This is very easy, just make a fraction
4/3 = 4/3
8/6 = 4/3
9/6.75 = 4/3
Hence the answer is 4/3
Answer:
1) x = 71
2) x = 117
5)
m<1: 35
m<2: 77
m<3: 52
m<4: 77
m<5: 65
m<6: 25
Step-by-step explanation:
1)
x + 41 + 68 = 180
x + 109 = 180
x = 71
2)
x + 47 + 16 = 180
x + 63 = 180
x = 117
3)
<2 + 103 = 180
<2 = 77
<1 + 68 + 77 = 180
<1 + 145 = 180
<1 = 35
<4 + 103 = 180
<4 = 77
<5 + 41 + 77 = 180
<5 + 115 = 180
<5 = 65
<6 + 65 = 90
<6 = 25
<3 + 103 + 25 = 180
<3 + 128 = 180
<3 = 52
