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FinnZ [79.3K]
3 years ago
7

Please help if you can <3

Mathematics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

1) x = 71

2) x = 117

5)

m<1: 35

m<2: 77

m<3: 52

m<4: 77

m<5: 65

m<6: 25

Step-by-step explanation:

1)

x + 41 + 68 = 180

x + 109 = 180

x = 71

2)

x + 47 + 16 = 180

x + 63 = 180

x = 117

3)

<2 + 103 = 180

<2 = 77

<1 + 68 + 77 = 180

<1 + 145 = 180

<1 = 35

<4 + 103 = 180

<4 = 77

<5 + 41 + 77 = 180

<5 + 115 = 180

<5 = 65

<6 + 65 = 90

<6 = 25

<3 + 103 + 25 = 180

<3 + 128 = 180

<3 = 52

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Slav-nsk [51]

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(10 points) From a group of 9 men and 7 women a committee consisting of 4 men and 4 women is to be formed. How many different co
alexgriva [62]

Answer:

a) 2450

b) 1890

c) 1050

Step-by-step explanation:

Given:

- Available Group = 9 M & 7 F

- Committee of= 4 M and 4 W to be formed

Find:

- (a) 2 of the men refuse to serve together?

- (a) 2 of the women refuse to serve together?

- (a) 1 man and 1 woman refuse to serve together?

Solution:

- The question pertains to a selection process, We will use combinations for each case as follows.

part a)

- Since 2 men cant be selected together. Then we have to discount for one man while selecting Man for the committee. Hence, the combinations are:

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part b)

- Since 2 women cant be selected together. Then we have to discount for one woman while selecting them for the committee. Hence, the combinations are:

                                   9C4 x 6C4 = 1890

part b)

- Since 1 women and a man cant be selected together. Then we have to discount for one woman and one man while selecting them for the committee. Hence, the combinations are:

                                   8C4 x 6C4 = 1050

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